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flatten sequences in a dictionary

Hi

I wondering if someone could give me a pointer. I have a dictionary
with the following structure:

testDict = dict(foo=((1,2,3),(1,4,3)), bar=((3,2,1),(9,8,7,)),
mumble=((1,2,3),))

I am trying to create a list of the the 3 element tuples using
itertools (just for a bit of fun). I'm trying this:

list(itertools.chain(testDict.itervalues())

but that's doesn't work. I think I need a way to convert the iterator
returned by itervalues() into a sequence of iterables. Any clues?

Thanks

Andy
Jan 9 '08 #1
1 1175
On Jan 9, 1:16 pm, ajcpp...@gmail.com wrote:
Hi

I wondering if someone could give me a pointer. I have a dictionary
with the following structure:

testDict = dict(foo=((1,2,3),(1,4,3)), bar=((3,2,1),(9,8,7,)),
mumble=((1,2,3),))

I am trying to create a list of the the 3 element tuples using
itertools (just for a bit of fun). I'm trying this:

list(itertools.chain(testDict.itervalues())
Close! Try:
list(itertools.chain(*testDict.itervalues())

--
Paul Hankin
Jan 9 '08 #2

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