generating list of sub lists

[cesco]

Hi,

is there a one-liner to accomplish the following task?

>From the list

l = ['string1', 'string2', 'string3']
generate the list of lists
l = [['string1'], ['string1', 'string2'], ['string1', 'string2',
'string3']]

Any help would be appreciated.

Thanks
Francesco

[=?ISO-8859-15?Q?Jes=FAs_Carrete_Monta=F1a?=]

cesco wrote:

l = ['string1', 'string2', 'string3']

l2=[l[:i+1] for i in range(len(l))]

[Rustom Mody]

On 9/16/07, cesco <fd**********@gmail.comwrote:

Hi,

is there a one-liner to accomplish the following task?

From the list

l = ['string1', 'string2', 'string3']
generate the list of lists
l = [['string1'], ['string1', 'string2'], ['string1', 'string2',
'string3']]

Any help would be appreciated.

Thanks
Francesco

>>l = [1,2,3,4,5]

>>[l[:i] for i in range(len(l))]

[[], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]

>>>

well almost works except for the first empty list. [Are you sure you
dont want it?]

Corrected

>>[l[:i+1] for i in range(len(l)-1)]

[[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]

Though I wonder if there is as neat a way as the first?

[Steve Holden]

Rustom Mody wrote:

On 9/16/07, cesco <fd**********@gmail.comwrote:

>Hi,

is there a one-liner to accomplish the following task?

>From the list

l = ['string1', 'string2', 'string3']
generate the list of lists
l = [['string1'], ['string1', 'string2'], ['string1', 'string2',
'string3']]

Any help would be appreciated.

Thanks
Francesco

>>>l = [1,2,3,4,5]

>>>[l[:i] for i in range(len(l))]

[[], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]
well almost works except for the first empty list. [Are you sure you
dont want it?]

Corrected

>>>[l[:i+1] for i in range(len(l)-1)]

[[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]

Though I wonder if there is as neat a way as the first?

>>[l[:i] for i in range(1, len(l))]

[[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]]

>>>

seems a slightly neater way to meet the requirement.

regards
steve
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[Ross Wilson]

cesco wrote:

Hi,

is there a one-liner to accomplish the following task?

>>From the list

l = ['string1', 'string2', 'string3']
generate the list of lists
l = [['string1'], ['string1', 'string2'], ['string1', 'string2',
'string3']]

Any help would be appreciated.

Thanks
Francesco

l = [l, l]

Ross

[Steven D'Aprano]

On Mon, 17 Sep 2007 20:52:14 +1000, Ross Wilson wrote:

cesco wrote:

>Hi,

is there a one-liner to accomplish the following task?

>>>From the list

l = ['string1', 'string2', 'string3'] generate the list of lists
l = [['string1'], ['string1', 'string2'], ['string1', 'string2',
'string3']]

Any help would be appreciated.

Thanks
Francesco

l = [l, l]

Ross

Did you *try* your suggestion before posting?

>>l = ['string1', 'string2', 'string3']
assert [l, l] == [['string1'], ['string1', 'string2'],

.... ['string1', 'string2', 'string3']]
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AssertionError
What you've suggested doesn't even come close to what the Original Poster
is asking for.
--
Steven