Question about recurssion

[Deathwing]

Hi everyone,

I have just programmed a very very simple calculator program, I am actually rather pleased. I would just like to know how I can make it so that every time the user has entered their input and an output has been returned by the program, the program jumps back to the start and ask the user to choose another option. Here is the code for my very very simple calculator program.

# my first very simple calculator
# this program only does basic arithmatic
 
print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#
 
WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4',)
 
print "\nHere are ur options:\n", options
 
 
choice = int(raw_input("Plese enter your operation choice: "))
 
if choice == 1:
    a = int(raw_input("enter value a: "))
    b = int(raw_input("enter value b: "))
    total = a+b
    print "\nThe total is:", total
 
 
elif choice == 2:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a-b
    print "\nThe total is:", total
 
 
elif choice == 3:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a/b
    print "\nThe total is:", total
 
 
elif choice == 4:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a*b
    print "\nThe total is:", total
 
else:
    print "\nYour choice is invalid"
 
 
 
raw_input("\nPres enter to exit.")
 
 
 
 
 
 
 

Thanks, -Deathwing

[bvdet]

Hi everyone,

I have just programmed a very very simple calculator program, I am actually rather pleased. I would just like to know how I can make it so that every time the user has entered their input and an output has been returned by the program, the program jumps back to the start and ask the user to choose another option. Here is the code for my very very simple calculator program.

# my first very simple calculator
# this program only does basic arithmatic
 
print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#
 
WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4',)
 
print "\nHere are ur options:\n", options
 
 
choice = int(raw_input("Plese enter your operation choice: "))
 
if choice == 1:
    a = int(raw_input("enter value a: "))
    b = int(raw_input("enter value b: "))
    total = a+b
    print "\nThe total is:", total
 
 
elif choice == 2:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a-b
    print "\nThe total is:", total
 
 
elif choice == 3:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a/b
    print "\nThe total is:", total
 
 
elif choice == 4:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a*b
    print "\nThe total is:", total
 
else:
    print "\nYour choice is invalid"
 
 
 
raw_input("\nPres enter to exit.")
 
 
 
 
 
 
 

Thanks, -Deathwing

You do not need recursion - you need a while loop:

# my first very simple calculator
# this program only does basic arithmatic
 
print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#
 
WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4', 'exit = 5')
 
print "\nHere are ur options:\n", options
 
while True:
    choice = int(raw_input("Plese enter your operation choice: "))
 
    if choice == 1:
        a = int(raw_input("enter value a: "))
        b = int(raw_input("enter value b: "))
        total = a+b
        print "\nThe total is:", total
 
 
    elif choice == 2:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a-b
        print "\nThe total is:", total
 
 
    elif choice == 3:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a/b
        print "\nThe total is:", total
 
 
    elif choice == 4:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a*b
        print "\nThe total is:", total
 
    elif choice == 5:
        break
 
    else:
        print "\nYour choice is invalid"
 
raw_input("\nPress enter to exit.")

If the user enters '5', the code 'breaks' out of the loop.

[Deathwing]

You do not need recursion - you need a while loop:

# my first very simple calculator
# this program only does basic arithmatic
 
print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#
 
WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4', 'exit = 5')
 
print "\nHere are ur options:\n", options
 
while True:
    choice = int(raw_input("Plese enter your operation choice: "))
 
    if choice == 1:
        a = int(raw_input("enter value a: "))
        b = int(raw_input("enter value b: "))
        total = a+b
        print "\nThe total is:", total
 
 
    elif choice == 2:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a-b
        print "\nThe total is:", total
 
 
    elif choice == 3:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a/b
        print "\nThe total is:", total
 
 
    elif choice == 4:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a*b
        print "\nThe total is:", total
 
    elif choice == 5:
        break
 
    else:
        print "\nYour choice is invalid"
 
raw_input("\nPress enter to exit.")

If the user enters '5', the code 'breaks' out of the loop.

ah... ic ic okay, I'll take a look and see what happens gracias.