Formatting the decimal value

[psbasha]

Hi,

I have the following row of data.

I/P:
20200107 1180.3489999999999 223.56720000000001 191.21019999999999

I would like to write this data to the file with two decimal places.

O/P:
20200107 1180.35 223.57 191.21

What is the syntax of it?.

Thanks
PSB

[bartonc]

Hi,

I have the following row of data.

I/P:
20200107 1180.3489999999999 223.56720000000001 191.21019999999999

I would like to write this data to the file with two decimal places.

O/P:
20200107 1180.35 223.57 191.21

What is the syntax of it?.

Thanks
PSB

>>> argStr = "20200107 1180.3489999999999 223.56720000000001 191.21019999999999"
>>> argList = argStr.split()
>>> a = int(argList[0])
>>> b, c, d = (float(x) for x in argList[1:])
>>> "%d %.2f %.2f %.2f" %(a, b, c, d)
'20200107 1180.35 223.57 191.21'
>>> 

[ghostdog74]

a = "20200107 1180.3489999999999 223.56720000000001 191.21019999999999"
print a.split()[0] ,
for i in [ "%.2f" % float(i) for i in a.split()[1:] ]: print i,
 

[bartonc]

a = "20200107 1180.3489999999999 223.56720000000001 191.21019999999999"
print a.split()[0] ,
for i in [ "%.2f" % float(i) for i in a.split()[1:] ]: print i,
 

So, is this a list comprehension to avoid using a generator due to the newness of generators?

[ghostdog74]

So, is this a list comprehension to avoid using a generator due to the newness of generators?

No. Its just a way to handle OP's problem. you can use generators too.
eg

...
for i in ("%.2f" % float(i) for i in a.split()[1:] ):
     print i
....
 

generators can conserve memory(supposedly from docs) better than list comprehension, especially with large lists.

[psbasha]

Thnaks for the reply,

The data I am getting in the dict and the co-ordinates are available in the list.I have to get the co-ordinates formating to 2 decimals and print to the file

I/P : {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}

Regard
PSB

[bartonc]

Thnaks for the reply,

The data I am getting in the dict and the co-ordinates are available in the list.I have to get the co-ordinates formating to 2 decimals and print to the file

I/P : {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}

Regard
PSB

Oh... Now you tell us:

>>> help(dict.get)
Help on method_descriptor:
 
get(...)
    D.get(k[,d]) -> D[k] if k in D, else d.  d defaults to None.
 
>>> d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
>>> key = 20200107
>>> l = d.get(key, (0, 0, 0))
>>> s = "%d %.2f %.2f %.2f" %(key, l[0], l[1], l[2])
>>> s
'20200107 1180.35 223.57 191.21'
>>> 

[bvdet]

Thnaks for the reply,

The data I am getting in the dict and the co-ordinates are available in the list.I have to get the co-ordinates formating to 2 decimals and print to the file

I/P : {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}

Regard
PSB

>>> d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
>>> print ' '.join([str(d.items()[0][0]), ] + [s for s in ['%0.2f' % float(i) for i in d.items()[0][1]]])
20200107 1180.35 223.57 191.21
>>> 

If you know the key as in:

for key in d:
    print ' '.join([str(key), ] + [s for s in ['%0.2f' % float(i) for i in d[key]]])
 

If you are writing multiple items from your dictionary to your file, be sure to add a newline character '\n' at the end of each line.

[bartonc]

Oh... Now you tell us:

>>> help(dict.get)
Help on method_descriptor:
 
get(...)
    D.get(k[,d]) -> D[k] if k in D, else d.  d defaults to None.
 
>>> d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
>>> key = 20200107
>>> l = d.get(key, (0, 0, 0))
>>> s = "%d %.2f %.2f %.2f" %(key, l[0], l[1], l[2])
>>> s
'20200107 1180.35 223.57 191.21'
>>> 

and for a real world application with more that one entry in the dictionary:

>>> d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999],
... 20200108:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999],
... 20200109:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
... 
>>> for k, v in d.items():
...     print "%d %.2f %.2f %.2f" %(k, v[0], v[1], v[2])
...     
20200107 1180.35 223.57 191.21
20200108 1180.35 223.57 191.21
20200109 1180.35 223.57 191.21
>>> 

[bartonc]

>>> d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
>>> print ' '.join([str(d.items()[0][0]), ] + [s for s in ['%0.2f' % float(i) for i in d.items()[0][1]]])
20200107 1180.35 223.57 191.21
>>> 

If you know the key as in:

for key in d:
    print ' '.join([str(key), ] + [s for s in ['%0.2f' % float(i) for i in d[key]]])
 

If you are writing multiple items from your dictionary to your file, be sure to add a newline character '\n' at the end of each line.

Dang, that's good! And fast; you beat me by one minute!

[bvdet]

Dang, that's good! And fast; you beat me by one minute!

Fastest is not necessarily the bestest! There was something in there that was redundant. Maybe this is it:

d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
 
print ' '.join([str(d.items()[0][0]), ] + ['%0.2f' % float(i) for i in d.items()[0][1]])
 
# If you know the key, as in:
for key in d:
    print ' '.join([str(key), ] + ['%0.2f' % float(i) for i in d[key]])

>>> 20200107 1180.35 223.57 191.21
20200107 1180.35 223.57 191.21
>>>

[ghostdog74]

just another variation

>>> d = {20200107:[ 1180.3489999999999, 223.56720000000001, 191.21019999999999]}
>>> for i,j in d.iteritems():
...  print "%s %s" % ( i , ' '.join(["%.2f" % float(f) for f in j]) )
...
20200107 1180.35 223.57 191.21
 
 

[psbasha]

Thanks to all.

It was really helpful for validating my geometry data.

-PSB

[bartonc]

Thanks to all.

It was really helpful for validating my geometry data.

-PSB

Which version did you end up going with?