Hi Spebola,
This behavior has been stated in the msdn.
Decimal.Round Method
When d is exactly halfway between two rounded values, the result is the
rounded value that has an even digit in the far right decimal position. For
example, when rounded to two decimals, the value 2.345 becomes 2.34 and the
value 2.355 becomes 2.36. This process is known as rounding toward even, or
rounding to nearest.
http://msdn.microsoft.com/library/de...us/cpref/html/
frlrfSystemMathClassAbsTopic.asp
The behavior also exist in VB6.
189847 INFO: New String and Format Functions in Visual Basic 6.0
http://support.microsoft.com/?id=189847
You may refer to link below for more details about business rule.
http://www.uop.edu/cop/psychology/St.../Rounding.html
According to Hurlburt, 1994 pg. 12,the procedure for finding the last digit
of a
measure is called "Rounding".
Rule 3- To prevent rounding bias, if the remainder is exactly 5, then round
the
last digit to the closest even number.Thus the number 3.55 (rounded to 1
digit)
would be 3.6 (rounding up) and the number 6.450 would round to 6.4
(rounding
down)if rounding to 1 decimal.
See page 12 in Hurlburt, R. (1994) Comprehending Behavioral Statistics,
Brooks/Cole, Pacific Grove, CA.
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--------------------
From: sp*****@swbell.net (spebola)
Newsgroups: microsoft.public.dotnet.languages.vb
Subject: vb.net 2003 rounding decimal value question
Date: 10 Oct 2003 09:32:51 -0700
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I am using vb.net 2003 professional and I get the following results
when using the round method:
dim Amount as decimal = 180.255
Amount = Amount.Round(Amount, 2)
Amount now contains 180.25. I need it to contain 180.26.
Any ideas?