HTML Encoded Translation

[Dave]

How can I translate this:

gi

to this:

"gi"

I've tried urllib.unencode and it doesn't work.

Thanks!

[Fredrik Lundh]

Dave wrote:

How can I translate this:

gi

to this:

"gi"

the easiest way is to run it through an HTML or XML parser (depending on
what the source is). or you could use something like this:

import re

def fix_charrefs(text):
def fixup(m):
text = m.group(0)
try:
if text[:3] == "&#x":
return unichr(int(text[3:-1], 16))
else:
return unichr(int(text[2:-1]))
except ValueError:
pass
return text # leave as is
return re.sub("&#?\w+;", fixup, text)

>>fix_charrefs("gi")

'gi'

also see:

http://effbot.org/zone/re-sub.htm#strip-html

I've tried urllib.unencode and it doesn't work.

those are HTML/XML character references, not encoded URL characters.

</F>

[Sybren Stuvel]

Dave enlightened us with:

How can I translate this:

gi

to this:

"gi"

I've tried urllib.unencode and it doesn't work.

As you put so nicely in the subject: it is HTML encoding, not URL
encoding. Those are two very different things! Try a HTML decoder,
you'll have more luck with that...

Sybren
--
Sybren Stüvel
Stüvel IT - http://www.stuvel.eu/

[Dave]

Got it, great. This worked like a charm. I knew I was barking up the
wrong tree with urllib, but I didn't know which tree to bark up...

Thanks!

Fredrik Lundh wrote:

Dave wrote:

How can I translate this:

gi

to this:

"gi"

the easiest way is to run it through an HTML or XML parser (depending on
what the source is). or you could use something like this:

import re

def fix_charrefs(text):
def fixup(m):
text = m.group(0)
try:
if text[:3] == "&#x":
return unichr(int(text[3:-1], 16))
else:
return unichr(int(text[2:-1]))
except ValueError:
pass
return text # leave as is
return re.sub("&#?\w+;", fixup, text)

>>fix_charrefs("gi")

'gi'

also see:

http://effbot.org/zone/re-sub.htm#strip-html

I've tried urllib.unencode and it doesn't work.

those are HTML/XML character references, not encoded URL characters.

</F>