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os.path.normpath

I am using a windows box and passing a string like "../foo/../foo2" to
normpath which then returns "..\\foo2". But if this string is going
into a webpage link it should really be "../foo".

Is there any way to tell os.path.normpath to act like we are an a unix
style box?

What about in the new python 2.5 Path class?

Nathan

Aug 9 '06 #1
3 4960

na***********@gmail.com wrote:
But if this string is going into a webpage link
http://docs.python.org/lib/module-urlparse.html

rd

Aug 9 '06 #2
At Wednesday 9/8/2006 15:45, na***********@gmail.com wrote:
>I am using a windows box and passing a string like "../foo/../foo2" to
normpath which then returns "..\\foo2". But if this string is going
into a webpage link it should really be "../foo".
You could just .replace('\\','/') on the resulting string. Or use the
urlparse module.
>Is there any way to tell os.path.normpath to act like we are an a unix
style box?
The fact than '/' is used as a path separator both on unix and on
HTTP URLs should be considered as a mere coincidence (in fact it isn't...)
URLs dont necesarily point to a real file on a real file system (Zope
is an example).

Gabriel Genellina
Softlab SRL

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Aug 10 '06 #3

na***********@gmail.com wrote:
I am using a windows box and passing a string like "../foo/../foo2" to
normpath which then returns "..\\foo2". But if this string is going
into a webpage link it should really be "../foo".

Is there any way to tell os.path.normpath to act like we are an a unix
style box?
Use posixpath.normpath() instead.

Aug 10 '06 #4

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