Changing entities

[Daniel]

Hello all

I need to build a program that check the sintax in a line:

SIZE (1 BYTE)

and change the correct number of bytes to the following format:

SIZE(1)

without the "BYTE" word. But, the number of bytes can be over 3 digits,
and the entitie can't have spaces but the correct number of bytes in
parentheses, like "SIZE (1024 BYTE)" to "SIZE(1024)".

Does anyone already done this or similar sintax using re?

Thank you

[Kent Johnson]

Daniel wrote:

Hello all

I need to build a program that check the sintax in a line:

SIZE (1 BYTE)

and change the correct number of bytes to the following format:

SIZE(1)

without the "BYTE" word. But, the number of bytes can be over 3 digits,
and the entitie can't have spaces but the correct number of bytes in
parentheses, like "SIZE (1024 BYTE)" to "SIZE(1024)".

import re
byter = re.compile(r'SIZE \((\d+) BYTE\)')
s = 'SIZE (1 BYTE)'
byter.sub(r'SIZE(\1)', s) 'SIZE(1)' s = 'SIZE (1024 BYTE)'
byter.sub(r'SIZE(\1)', s)

'SIZE(1024)'

Kent

[Daniel]

Hi Kent

Thanks for your help, it worked sucessfully. I have another question, I
think it is a stupid and simple but...

I need match a regular expression, change it erasing the other strings
after this. Just like:

a = "I'm going send to out of space, find another race"

And I want to match "space" instance, and erase the other.

Thank you

[Kent Johnson]

Daniel wrote:

I need match a regular expression, change it erasing the other strings
after this. Just like:

a = "I'm going send to out of space, find another race"

And I want to match "space" instance, and erase the other.

If you mean you want to get rid of everything after 'space', this will do it:

import re
a = "I'm going send to out of space, find another race"
re.sub('space.*', 'space', a)

"I'm going send to out of space"

You should read this and learn to make your own regexes:
http://www.amk.ca/python/howto/regex/

Kent

[Daniel]

Hi Kent

This isn't work with the following line:
FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)

byter = re.compile(r'SIZE \((\d+) BYTE\)')
s = 'SIZE (1 BYTE)'
byter.sub(r'SIZE(\1)', s) 'SIZE(1)' byter.sub(r'SIZE(\1)', line) 'FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)' line 'FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)'

Any idea? :-p

[Daniel]

Hi Kent

This isn't work with the following line:
FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)

byter = re.compile(r'SIZE \((\d+) BYTE\)')
s = 'SIZE (1 BYTE)'
byter.sub(r'SIZE(\1)', s) 'SIZE(1)' byter.sub(r'SIZE(\1)', line) 'FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)' line 'FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)'

Any idea? :-p

[Kent Johnson]

Daniel wrote:

Hi Kent

This isn't work with the following line:
FieldGraphic56 ::= GraphicString EBCDIC BC= " " SIZE (56
BYTES)

byter = re.compile(r'SIZE \((\d+) BYTE\)')

Because the string doesn't match the pattern, can you see the difference? Do you understand what the regex is looking for?

Another good way to learn about regexes is with the Regex Demo program distributed with Python. Look for Tools\Scripts\redemo.py

Kent