I have seen something about this beofore on this forum, but my google search
didn't come up with the answer I am looking for.
I have a list of tuples. Each tuple is in the following format:
("data", "moredata", "evenmoredata", "date string")
The date string is my concern. This is the date stamp from an email.
The problem is that I have a whole bunch of variations when it comes to the
format that the date string is in. For example I could have the following
two tuples:
("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
("data", "moredata", "evenmoredata", "Thursday, 22 January 2004 03:15:06")
I know there is some way to use the date string from each of these to get a
date usable by python, but I cannot figure it out.
I was trying to use time.strptime but have been unsuccesful thus far.
Any help is appreciated.
11  1883 
Amy,
I hope there is a better way but, if you go here: http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote: I have seen something about this beofore on this forum, but my google search
didn't come up with the answer I am looking for.
I have a list of tuples. Each tuple is in the following format:
("data", "moredata", "evenmoredata", "date string")
The date string is my concern. This is the date stamp from an email.
The problem is that I have a whole bunch of variations when it comes to the
format that the date string is in. For example I could have the following
two tuples:
("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
("data", "moredata", "evenmoredata", "Thursday, 22 January 2004 03:15:06")
I know there is some way to use the date string from each of these to get a
date usable by python, but I cannot figure it out.
I was trying to use time.strptime but have been unsuccesful thus far.
Any help is appreciated.
No it won't. Unfortunatly I don't necessarily have a comma delimited date
string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats. I
would like to parse through them and get a comparable format so that I can
display them in chronological order.
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote: I have seen something about this beofore on this forum, but my google
search didn't come up with the answer I am looking for.
I have a list of tuples. Each tuple is in the following format:
("data", "moredata", "evenmoredata", "date string")
The date string is my concern. This is the date stamp from an email.
The problem is that I have a whole bunch of variations when it comes to
the format that the date string is in. For example I could have the
following two tuples:
("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
("data", "moredata", "evenmoredata", "Thursday, 22 January 2004
03:15:06")
I know there is some way to use the date string from each of these to
get a date usable by python, but I cannot figure it out.
I was trying to use time.strptime but have been unsuccesful thus far.
Any help is appreciated.
"Amy G" <am*******@cox.net> wrote in message
news:PRgQb.16209$AA6.9881@fed1read03... No it won't. Unfortunatly I don't necessarily have a comma delimited date
string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats. I
would like to parse through them and get a comparable format so that I can
display them in chronological order.
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote: I have seen something about this beofore on this forum, but my google search didn't come up with the answer I am looking for.
I have a list of tuples. Each tuple is in the following format:
("data", "moredata", "evenmoredata", "date string")
The date string is my concern. This is the date stamp from an email.
The problem is that I have a whole bunch of variations when it comes
to the format that the date string is in. For example I could have the following two tuples:
("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
("data", "moredata", "evenmoredata", "Thursday, 22 January 2004 03:15:06")
I know there is some way to use the date string from each of these to get a date usable by python, but I cannot figure it out.
I was trying to use time.strptime but have been unsuccesful thus far.
Any help is appreciated.
This was asked and answered earlier today
See: https://moin.conectiva.com.br/DateUtil
from dateutil.parser import parse
parse("Thursday, 22 January 2004 03:15:06")
datetime.datetime(2004, 1, 22, 3, 15, 6) parse("Thursday, January 22, 2004, 03:15:06")
datetime.datetime(2004, 1, 22, 3, 15, 6) parse("2004, Thursday, 22 January 03:15:06")
datetime.datetime(2004, 1, 22, 3, 15, 6)
That is exactly what I am looking for. However I don't have the module
installed. Where can I get it?
"Michael Spencer" <mi*****@telcopartners.com> wrote in message
news:K4********************@comcast.com... "Amy G" <am*******@cox.net> wrote in message
news:PRgQb.16209$AA6.9881@fed1read03... No it won't. Unfortunatly I don't necessarily have a comma delimited
date string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats.
I would like to parse through them and get a comparable format so that I
can display them in chronological order.
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote:
> I have seen something about this beofore on this forum, but my
google search > didn't come up with the answer I am looking for.
>
> I have a list of tuples. Each tuple is in the following format:
>
> ("data", "moredata", "evenmoredata", "date string")
>
> The date string is my concern. This is the date stamp from an
email. > The problem is that I have a whole bunch of variations when it comes
to the > format that the date string is in. For example I could have the
following > two tuples:
>
> ("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
> ("data", "moredata", "evenmoredata", "Thursday, 22 January 2004
03:15:06") >
> I know there is some way to use the date string from each of these
to get a > date usable by python, but I cannot figure it out.
> I was trying to use time.strptime but have been unsuccesful thus
far. >
> Any help is appreciated.
>
>
This was asked and answered earlier today
See: https://moin.conectiva.com.br/DateUtil
from dateutil.parser import parse
parse("Thursday, 22 January 2004 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6) parse("Thursday, January 22, 2004, 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6) parse("2004, Thursday, 22 January 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6)
Amy> The following three date strings is another example of the various
Amy> date formats I will encounter here.
Amy> Thursday, 22 January 2004 03:15:06
Amy> Thursday, January 22, 2004, 03:15:06
Amy> 2004, Thursday, 22 January 03:15:06
Assuming you won't have any ambiguous dates (like 1/3/04), just define
regular expressions which label the various fields of interest, then match
your string against them until you get a hit. For
example, the first would be matched by this: import re
pat = re.compile(r'(?P<wkday>[A-Z][a-z]+),\s+(?P<day>[0-9]{1,2})\s+'
... r'(?P<month>[A-Z][a-z]+)\s+(?P<year>[0-9]{4,4})') mat = pat.match('Thursday, 22 January 2004 03:15:06')
mat
<_sre.SRE_Match object at 0x487498> mat.groups()
('Thursday', '22', 'January', '2004') mat.group('month')
'January'
etc. (Extending the regexp to accommodate the time is left as an exercise.)
Once you have a match, pull out the relevant bits, maybe tweak them a bit
(int()-ify things), then create a datetime instance from the result.
I do something like this in my dates module. It's old and ugly though: http://manatee.mojam.com/~skip/python/
Search for "date-parsing module". This was written long before the datetime
module was available and was used for for a slightly different purpose. It
recognizes a number of different date range formats in addition to
individual dates. You might be able to snag some regular expression ideas
from it though.
Skip
When I tried to do the make install I get the following error message:
warning: install: modules installed to '/usr/lib/python2.2/site-packages/',
which is not in Python's module search path (sys.path) -- you'll have to
change the search path yourself
How do I correct this. Sorry for the newb question.
"Michael Spencer" <mi*****@telcopartners.com> wrote in message
news:K4********************@comcast.com... "Amy G" <am*******@cox.net> wrote in message
news:PRgQb.16209$AA6.9881@fed1read03... No it won't. Unfortunatly I don't necessarily have a comma delimited
date string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats.
I would like to parse through them and get a comparable format so that I
can display them in chronological order.
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote:
> I have seen something about this beofore on this forum, but my
google search > didn't come up with the answer I am looking for.
>
> I have a list of tuples. Each tuple is in the following format:
>
> ("data", "moredata", "evenmoredata", "date string")
>
> The date string is my concern. This is the date stamp from an
email. > The problem is that I have a whole bunch of variations when it comes
to the > format that the date string is in. For example I could have the
following > two tuples:
>
> ("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
> ("data", "moredata", "evenmoredata", "Thursday, 22 January 2004
03:15:06") >
> I know there is some way to use the date string from each of these
to get a > date usable by python, but I cannot figure it out.
> I was trying to use time.strptime but have been unsuccesful thus
far. >
> Any help is appreciated.
>
>
This was asked and answered earlier today
See: https://moin.conectiva.com.br/DateUtil
from dateutil.parser import parse
parse("Thursday, 22 January 2004 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6) parse("Thursday, January 22, 2004, 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6) parse("2004, Thursday, 22 January 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6)
Some extra info... when I get this import sys
sys.path
['', '/usr/local/lib/python2.2', '/usr/local/lib/python2.2/plat-freebsd5',
'/usr/local/lib/python2.2/lib-tk', '/usr/local/lib/python2.2/lib-dynload',
'/usr/local/lib/python2.2/site-packages']
Doesn't that mean that the directory is already in the path???
"Michael Spencer" <mi*****@telcopartners.com> wrote in message
news:K4********************@comcast.com... "Amy G" <am*******@cox.net> wrote in message
news:PRgQb.16209$AA6.9881@fed1read03... No it won't. Unfortunatly I don't necessarily have a comma delimited
date string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats.
I would like to parse through them and get a comparable format so that I
can display them in chronological order.
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote:
> I have seen something about this beofore on this forum, but my
google search > didn't come up with the answer I am looking for.
>
> I have a list of tuples. Each tuple is in the following format:
>
> ("data", "moredata", "evenmoredata", "date string")
>
> The date string is my concern. This is the date stamp from an
email. > The problem is that I have a whole bunch of variations when it comes
to the > format that the date string is in. For example I could have the
following > two tuples:
>
> ("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
> ("data", "moredata", "evenmoredata", "Thursday, 22 January 2004
03:15:06") >
> I know there is some way to use the date string from each of these
to get a > date usable by python, but I cannot figure it out.
> I was trying to use time.strptime but have been unsuccesful thus
far. >
> Any help is appreciated.
>
>
This was asked and answered earlier today
See: https://moin.conectiva.com.br/DateUtil
from dateutil.parser import parse
parse("Thursday, 22 January 2004 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6) parse("Thursday, January 22, 2004, 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6) parse("2004, Thursday, 22 January 03:15:06") datetime.datetime(2004, 1, 22, 3, 15, 6)
Okay. I fixed the problem somewhat. I moved the dateutil directory over to
/usr/local/lib/python2.2/site-packages and I can now import dateutil. But a
call like this:
from dateutil.parser import parse
results in this error:
ImportError: cannot import name parse
I can 'from dateutil.parser import *' but cannot use parse after that.
I can also 'from dateutil import parser' but that doesn't help either.
Sorry for my inexperience here. Thanks for all of the help already.
"Amy G" <am*******@cox.net> wrote in message
news:PRgQb.16209$AA6.9881@fed1read03... No it won't. Unfortunatly I don't necessarily have a comma delimited date
string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats. I
would like to parse through them and get a comparable format so that I can
display them in chronological order.
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
Amy G wrote: I have seen something about this beofore on this forum, but my google search didn't come up with the answer I am looking for.
I have a list of tuples. Each tuple is in the following format:
("data", "moredata", "evenmoredata", "date string")
The date string is my concern. This is the date stamp from an email.
The problem is that I have a whole bunch of variations when it comes
to the format that the date string is in. For example I could have the following two tuples:
("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
("data", "moredata", "evenmoredata", "Thursday, 22 January 2004 03:15:06")
I know there is some way to use the date string from each of these to get a date usable by python, but I cannot figure it out.
I was trying to use time.strptime but have been unsuccesful thus far.
Any help is appreciated.
"Amy G" <am*******@cox.net> wrote in message
news:4GfQb.16187$AA6.14368@fed1read03... I have seen something about this beofore on this forum, but my google
search didn't come up with the answer I am looking for.
I have a list of tuples. Each tuple is in the following format:
("data", "moredata", "evenmoredata", "date string")
The date string is my concern. This is the date stamp from an email.
The problem is that I have a whole bunch of variations when it comes to
the format that the date string is in. For example I could have the following
two tuples:
("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
("data", "moredata", "evenmoredata", "Thursday, 22 January 2004 03:15:06")
I know there is some way to use the date string from each of these to get
a date usable by python, but I cannot figure it out.
I was trying to use time.strptime but have been unsuccesful thus far.
Any help is appreciated.
This is what I use to parse dates of unknown provinance.
It's laughably overengineered, and I don't include the day
of the week or the time. Given your examples, though,
those should be easy enough to deal with.
HTH
John Roth
class DateContainer(object):
_typeDict = {}
_stringValue = ""
_typeDict["stringValue"] = "String"
_typeDict["value"] = "String"
_value = ""
year = 1
month = 1
day = 1
bc = ""
def _checkUserFriendlyDate(self, date):
# The rules for a user friendly date are:
# 1. The year must be at least three digits, including
# leading zeroes if necessary. Day and numeric month
# may be no longer than 2 digits.
# 2. The month may be alphabetic or numeric. If it's
# alphabetic, it must be at least three letters long.
# 3. The epoch may be ad, bc, bce or ce. If omitted, it's
# assumed to be ad.
# 4. After removing the year, epoch and an alphabetic month,
# the remaining single piece is the day, or the piece that
# is greater than 12.
# 5. If two pieces remain, the first is the month, the second
# is the day. Both are between 1 and 12, inclusive.
partList = dateTimeParse(date)
if not(2 < len(partList) < 5):
raise ValueError, "incorrect part list: %s" % (partList,)
bc = self._findBC(partList)
if len(partList) != 3:
return "too many components in date: '%s'" % date
year = self._findYear(partList)
month = self._findAlphaMonth(partList)
if month != 0:
day = partList[0]
else:
day = self._findDay(partList)
if day:
month = partList[0]
else:
month, day = partList
year = self._checkNum(year, 4712)
day = self._checkNum(day, 31)
month = self._checkNum(month, 12)
if bc in ("AD", "CE"):
bc = ""
self.year, self.month, self.day, self.bc = year, month, day, bc
return True
def _checkNum(self, num, limit):
result = int(num)
if result > limit:
raise ValueError, "number '%s' out of range '%s'" % (num, limit)
return result
def _findBC(self, partList):
for i in range(len(partList)):
word = partList[i]
if word in ("AD", "BC", "CE", "BCE"):
del partList[i]
return word
# XXX if len(partList > 3): error
return ""
def _findYear(self, partList):
for i in range(len(partList)):
word = partList[i]
if len(word) > 2 and word.isdigit():
del partList[i]
return word
raise ValueError
def _findAlphaMonth(self, partList):
for i in range(len(partList)):
word = partList[i]
if word.isalpha():
del partList[i]
return ['JAN', 'FEB', 'MAR', 'APR', 'MAY', 'JUN',
'JUL', 'AUG', 'SEP', 'OCT', 'NOV',
'DEC'].index(word[:3]) + 1
return 0
def _findDay(self, partList):
for i in range(len(partList)):
word = partList[i]
if word.isdigit() and int(word) > 12:
del partList[i]
return word
return ""
def _getStringValue(self):
return self._stringValue
def _setStringValue(self, value):
self._checkUserFriendlyDate(value)
self._stringValue = value
_typeDict["stringValue"] = "String"
stringValue = property(_getStringValue, _setStringValue,
doc="User Friendly Date")
def _getValue(self):
isoDate = "%04u-%02u-%02u %s" % (self.year, self.month, self.day,
self.bc)
return isoDate.strip()
def checkISODate(self, value):
year = self._checkNum(value[:4], 4712)
month = self._checkNum(value[5:7], 12)
day = self._checkNum(value[8:10], 31)
if len(value) > 10:
bc = value[11:]
if not (bc.upper() in ("AD", "BC", "BCE", "CE")):
raise ValueError
if bc in ("AD", "CE"):
bc = ""
self.year, self.month, self.day, self.bc = year, month, day, bc
return
def _setValue(self, value):
self._checkISODate(value)
isoDate = "%04u-%02u-%02u %s" % (self.year, self.month, self.day,
self.bc)
self.stringValue = isoDate
return None
value = property(_getValue, _setValue,
doc = "ISO Standard Format Date")
#!/usr/local/bin/python -O
#NOTE: add missing MONTHS; DAYS not used
import datetime
import string
dateList = ["Fri, 23 Jan 2004 00:06:15",
"Thursday, 22 January 2004 03:15:06",
"Thursday, January 22, 2004, 03:15:06",
"2004, Thursday, 22 January 03:15:06"]
MONTHS = [("JANUARY",1),
("JAN",1),
("FEBRUARY",2),
("FEB",2),
#etc
]
DAYS = [("Monday",0),
("Mon",0),
#........
("Thursday",3),
("Thur",3)
]
#--------------------------------------------------------------------
def GetMonthInt(mstr):
#print "mstr=",mstr
for t in MONTHS:
if t[0].find(mstr) > -1:
return t[1]
return -1
#--------------------------------------------------------------------
class MyDateTime:
def __init__(self,oddstr):
tokens = oddstr.split()
temp = []
for t in tokens:
if t.find(":") > -1:
continue
if t[-1] == ',':
t = t[:-1]
temp.append(t)
tokens = temp
#for t in tokens:
# print t
year = -1
month = -1
day = -1
for t in tokens:
if t[0] in string.digits:
x = int(t)
if x > 31:
year = x
else:
day = x
continue
t = t.upper()
if t[0] in string.ascii_uppercase:
x = GetMonthInt(t)
if x <> -1:
month = x
continue
if year > -1 and month > -1 and day > -1:
self.Date = datetime.date(year,month,day)
else:
self.Date = None
def Show(self):
print self.Date.ctime()
#--------------------------------------------------------------------
if __name__ == '__main__':
for date in dateList:
dt = MyDateTime(date)
dt.Show()
[Fixed top-posts: please add future comments at the bottom]
Amy G wrote:
> I have seen something about this beofore on this forum, but my
google search > didn't come up with the answer I am looking for.
>
> I have a list of tuples. Each tuple is in the following format:
>
> ("data", "moredata", "evenmoredata", "date string")
>
> The date string is my concern. This is the date stamp from an
email. > The problem is that I have a whole bunch of variations when it comes to the > format that the date string is in. For example I could have the
following > two tuples:
>
> ("data", "moredata", "evenmoredata", "Fri, 23 Jan 2004 00:06:15")
> ("data", "moredata", "evenmoredata", "Thursday, 22 January 2004
03:15:06") >
> I know there is some way to use the date string from each of these
to get a > date usable by python, but I cannot figure it out.
> I was trying to use time.strptime but have been unsuccesful thus
far. >
> Any help is appreciated.
>
"wes weston" <ww*****@att.net> wrote in message
news:MF*********************@bgtnsc05-news.ops.worldnet.att.net... Amy,
I hope there is a better way but, if you go here:
http://www.python.org/doc/current/li...time-date.html
The new datetime module may help. This and the time mod
should get you where you want to go.
list = strdate.split(", ")
daystr = list[0]
daynum = int(list[1])
monthstr = list[2]
year = int(list[3])
#funct to get a month int is needed
d = datetime.Date(y,m,d)
wes
---------------------------------------
>
"Amy G" <am*******@cox.net> wrote in message
news:PRgQb.16209$AA6.9881@fed1read03... No it won't. Unfortunatly I don't necessarily have a comma delimited
date string. Thanks for the input though.
The following three date strings is another example of the various date
formats I will encounter here.
Thursday, 22 January 2004 03:15:06
Thursday, January 22, 2004, 03:15:06
2004, Thursday, 22 January 03:15:06
All of these are essentially the same date... just in various formats.
I would like to parse through them and get a comparable format so that I
can display them in chronological order.
"Amy G" <am*******@cox.net> wrote in message
news:n7iQb.16224$AA6.5862@fed1read03... Okay. I fixed the problem somewhat. I moved the dateutil directory over
to /usr/local/lib/python2.2/site-packages and I can now import dateutil. But
a call like this:
from dateutil.parser import parse
results in this error:
ImportError: cannot import name parse
I can 'from dateutil.parser import *' but cannot use parse after that.
I can also 'from dateutil import parser' but that doesn't help either.
Sorry for my inexperience here. Thanks for all of the help already.
Amy:
The docstring of the dateutil package:
"""
Copyright (c) 2003 Gustavo Niemeyer <ni******@conectiva.com>
This module offers extensions to the standard python 2.3+
datetime module.
"""
__author__ = "Gustavo Niemeyer <ni******@conectiva.com>"
__license__ = "PSF License"
notes that it requires the datetime module (new in Python 2.3). It appears
that you are using 2.2. Can you install 2.3.3?
If you need to stick with 2.2, the question of using datetime in 2.2 was
answered in http://groups.google.com/groups?q=py...hon.org&rnum=2
with a pointer to a "workalike" module, see: http://cvs.zope.org/Zope3/src/datetime/
I have not tested whether this works with dateutil
Cheers
Michael This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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