Find and Delete all files with .xxx extension

[hokiegal99]

The below code does what I need it to do, but I thought that using
something like ext = os.path.splitex t(fname) and then searching ext[1]
for '.mp3' would be a much more accurate approach to solving this
problem. Could someone demonstrate how to search ext[1] for a specific
string? This script works great for deleting illegal music on user
machines ;)

Thanks!!!
import os, string
setpath = raw_input("Ente r the path: ") #This can be hard coded.
for root, dirs, files in os.walk(setpath , topdown=False):
for fname in files:
s = string.find(fna me, '.mp3')
if s >=1:
fpath = os.path.join(ro ot,fname)
os.remove(fpath )
print "Removed", fpath, "\n"

[Georgy Pruss]

"hokiegal99 " <ho********@hot mail.com> wrote in message news:3F******** ******@hotmail. com...
| s = string.find(fna me, '.mp3')
| if s >=1:

I would say: if fname.lower().e ndswith( '.mp3' ):

[William Park]

hokiegal99 <ho********@hot mail.com> wrote:

The below code does what I need it to do, but I thought that using
something like ext = os.path.splitex t(fname) and then searching ext[1]
for '.mp3' would be a much more accurate approach to solving this
problem. Could someone demonstrate how to search ext[1] for a specific
string? This script works great for deleting illegal music on user
machines ;)

Thanks!!!
import os, string
setpath = raw_input("Ente r the path: ") #This can be hard coded.
for root, dirs, files in os.walk(setpath , topdown=False):
for fname in files:
s = string.find(fna me, '.mp3')
if s >=1:
fpath = os.path.join(ro ot,fname)
os.remove(fpath )
print "Removed", fpath, "\n"

FYI, in shell, you would go
find . -type f -name '*.mp3' | xargs rm

--
William Park, Open Geometry Consulting, <op**********@y ahoo.ca>
Linux solution for data management and processing.

[Fredrik Lundh]

"hokiegal99 " wrote:

The below code does what I need it to do, but I thought that using
something like ext = os.path.splitex t(fname) and then searching ext[1]
for '.mp3' would be a much more accurate approach to solving this
problem. Could someone demonstrate how to search ext[1] for a specific
string?

to quote myself from an earlier reply to you:

os.path.splitex t(fname) splits a filename into prefix and extension
parts:

os.path.splitex t("hello") ('hello', '') os.path.splitex t("hello.doc" ) ('hello', '.doc') os.path.splitex t("hello.DOC" ) ('hello', '.DOC') os.path.splitex t("hello.foo" )

('hello', '.foo')

in other words, ext[1] *is* the extension. if you want to look for mp3's,
just compare the seconrd part to the string ".mp3":

for fname in files:
name, ext = os.path.splitex t(fname)
if ext == ".mp3":
# ... do something ...

if you want to look for mp3, MP3, Mp3, etc, you can use the "lower"
method on the extension:

for fname in files:
name, ext = os.path.splitex t(fname)
ext = ext.lower()
if ext == ".mp3":
# ... do something with mp3 files ...
if ext == ".foo":
# ... do something with foo files ...

</F>

[hokiegal99]

"Georgy Pruss" <se************ *@hotmail.com> wrote in message news:<Cv******* **************@ twister.southea st.rr.com>...

"hokiegal99 " <ho********@hot mail.com> wrote in message news:3F******** ******@hotmail. com...
| s = string.find(fna me, '.mp3')
| if s >=1:

I would say: if fname.lower().e ndswith( '.mp3' ):

Why the '.lower()' part? Wouldn't if fname.endswith( '.mp3'): work just
as well, or am I missing something here?

[hokiegal99]

"Fredrik Lundh" <fr*****@python ware.com> wrote

to quote myself from an earlier reply to you:

os.path.splitex t(fname) splits a filename into prefix and extension
parts:

>>> os.path.splitex t("hello") ('hello', '') >>> os.path.splitex t("hello.doc" ) ('hello', '.doc') >>> os.path.splitex t("hello.DOC" ) ('hello', '.DOC') >>> os.path.splitex t("hello.foo" )

('hello', '.foo')

in other words, ext[1] *is* the extension.

Yes, I know that. You helped me to understand that in a earlier,
different question.

if you want to look for mp3, MP3, Mp3, etc, you can use the "lower"
method on the extension:

for fname in files:
name, ext = os.path.splitex t(fname)
ext = ext.lower()
if ext == ".mp3":
# ... do something with mp3 files ...
if ext == ".foo":
# ... do something with foo files ...

Thank you for this example, it's exactly what I was thinking of. I
didn't know that I could use an equivalent comparison to determine
whether or not ext[1] contained the string I wanted to remove, that's
all I was asking.

After reading over the various replies and testing them, I think that
this is the best solution:

if fname.lower().e ndswith('.mp3') :
remove...

Thanks again for the examples.

[Mark McEahern]

On Sun, 2003-12-14 at 09:06, hokiegal99 wrote:

I would say: if fname.lower().e ndswith( '.mp3' ):

Why the '.lower()' part? Wouldn't if fname.endswith( '.mp3'): work just
as well, or am I missing something here?

Because the filename might be WHATEVER.MP3 and endswith, presumably, is
case-sensitive.

Cheers,

// m

[Heike C. Zimmerer]

William Park <op**********@y ahoo.ca> writes:

hokiegal99 <ho********@hot mail.com> wrote:

import os, string
setpath = raw_input("Ente r the path: ") #This can be hard coded.
for root, dirs, files in os.walk(setpath , topdown=False):
for fname in files:
s = string.find(fna me, '.mp3')
if s >=1:
fpath = os.path.join(ro ot,fname)
os.remove(fpath )
print "Removed", fpath, "\n"

FYI, in shell, you would go
find . -type f -name '*.mp3' | xargs rm

Which will fail if the file name contains any spaces or other special
characters (not too unusual for .mp3 - Files).

- Heike

[William Park]

Heike C. Zimmerer <us********@hcz im.de> wrote:

William Park <op**********@y ahoo.ca> writes:

hokiegal99 <ho********@hot mail.com> wrote:

import os, string
setpath = raw_input("Ente r the path: ") #This can be hard coded.
for root, dirs, files in os.walk(setpath , topdown=False):
for fname in files:
s = string.find(fna me, '.mp3')
if s >=1:
fpath = os.path.join(ro ot,fname)
os.remove(fpath )
print "Removed", fpath, "\n"

FYI, in shell, you would go
find . -type f -name '*.mp3' | xargs rm

Which will fail if the file name contains any spaces or other special
characters (not too unusual for .mp3 - Files).

In which case, you look up 'man find xargs' and edit the command to
find ... -print0 | xargs -0 ...

--
William Park, Open Geometry Consulting, <op**********@y ahoo.ca>
Linux solution for data management and processing.

[hokiegal99]

William Park <op**********@y ahoo.ca> wrote in message news:<br******* *****@ID-99293.news.uni-berlin.de>...

Heike C. Zimmerer <us********@hcz im.de> wrote:

William Park <op**********@y ahoo.ca> writes:

hokiegal99 <ho********@hot mail.com> wrote:
> import os, string
> setpath = raw_input("Ente r the path: ") #This can be hard coded.
> for root, dirs, files in os.walk(setpath , topdown=False):
> for fname in files:
> s = string.find(fna me, '.mp3')
> if s >=1:
> fpath = os.path.join(ro ot,fname)
> os.remove(fpath )
> print "Removed", fpath, "\n"

FYI, in shell, you would go
find . -type f -name '*.mp3' | xargs rm

Which will fail if the file name contains any spaces or other special
characters (not too unusual for .mp3 - Files).

In which case, you look up 'man find xargs' and edit the command to
find ... -print0 | xargs -0 ...

What would you man on a Windows box??? Not everyone has a unix shell,
and not everyone wants/needs one. None of our users use Linux/Unix.
They all use Windows XP or Mac OS X. So, you shouldn't assume that I'm
running Linux or some other type of Unix. I do as an admin/developer,
but that's not the point. The above python script will run on Windows,
Linux, OS X, etc. and it makes for much easier reading. This is a
python forum. So, you're off-topic.