Re: problems with opening files due to file's path

[Alexnb]

Gerhard Häring wrote:

Alexnb wrote:

>Okay, so what I want my program to do it open a file, a music file in
specific, and for this we will say it is an .mp3. Well, I am using the
system() command from the os class. [...]

system("\"C:\D ocuments and Settings\Alex\M y Documents\My
Music\Rhapsody \Bryanbros\Weez er\(2001)\04 - Island In The Sun.wma\"")
[...]

Try os.startfile() instead. It should work better.

-- Gerhard

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No, it didn't work, but it gave me some interesting feedback when I ran it
in the shell. Heres what it told me:

>>os.startfile( "C:\Documen ts and Settings\Alex\M y Documents\My
Music\Rhapsod y\Bryanbros\Jas on Mraz\I'm Yours (Single)\01 - I'm
Yours.wma")

Traceback (most recent call last):
File "<pyshell#1 0>", line 1, in <module>
os.startfile("C :\Documents and Settings\Alex\M y Documents\My
Music\Rhapsody\ Bryanbros\Jason Mraz\I'm Yours (Single)\01 - I'm Yours.wma")

WindowsError: [Error 2] The system cannot find the file specified:
"C:\\Docume nts and Settings\\Alex\ \My Documents\\My
Music\\Rhapsody \\Bryanbros\\Ja son Mraz\\I'm Yours (Single)\x01 - I'm
Yours.wma"

See it made each backslash into two, and the one by the parenthesis and the
0 turned into an x....
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[Carsten Haese]

Alexnb wrote:

I don't get why yall are being so rude about this.

We're frustrated with your apparent inability to understand anything
we're saying.

My problem is this; the
path, as a variable conflicts with other characters in the path, creating
escape characters I don't want, so I need a way to send the string to the
os.startfile() in raw, or, with all the backslashes doubled.

No, no, no, no, NO! That is not your problem! You are drawing unfounded
conclusions from the fact that you had to double up backslashes when the
filename came from a string literal. The situation is entirely different
when the filename comes from user input. No doubling up of backslashes
is necessary when the filename comes from user input. TRUST ME!

For simplicity, start with this code to convince yourself:

import os
filename = raw_input("Plea se enter a filename: ")
os.startfile(fi lename)

Once you get that to work, replace raw_input with a function that gets
the filename from your GUI.

Hope this helps,

--
Carsten Haese
http://informixdb.sourceforge.net

[Alexnb]

Well, I don't understand why I don't need to change anything because say I
run that code, which goes straight from the entry box to the startfile()
function. It doesn't work with some of the paths, that is the whole problem.
the problem is when I enter a path with those certain characters next to
each other. Everyone seems like there is some huge thing that I am
missing... and I don't know what it is, because when I run that code, with
that path I was talking about, I get an error, and it shows me that it is
because of the \0.
Jerry Hill wrote:

>
On Wed, Jun 11, 2008 at 4:16 PM, Alexnb <al********@gma il.comwrote:

>>
I posted the underlying code, but I haven't made the GUI code because if
I
can't get the underlying code right it doesn't matter, well in my eyes it
doesn't but I am probably wrong. But it will look somehting like this:

What you're missing is that all of the problems you're having with
escape characters *only apply to string literals inside your python
source code.* If you're getting the string from the console, you
don't need to escape or change anything. If you're getting the string
from a Tk text box, you don't need to escape or change anything. If
you're getting the string from the filesystem, you don't need to
escape or change anything.

The only place you have to be careful is when you type out a literal
string inside your .py source code. When you do that, you need to
properly escape backslashes, either by putting them in raw strings, or
by doubling up your backslashes.

If you haven't already, reread the section of the python tutorial
about string literals: http://docs.python.org/tut/node5.html.

--
Jerry
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[Carsten Haese]

Alexnb wrote:

Okay, so I wrote some code of basically what I will be doing, only with
exactly what I need for this part of the program but here you go: [...]

Finally...

path = "\"" + path + "\""

That line of code is unnecessary. Delete it.

--
Carsten Haese
http://informixdb.sourceforge.net

[Alexnb]

Haha, okay well sorry that I was being so stupid, but I get it now and I
apoligize for causing you all the frustration. But I did get it to work
finally.
Carsten Haese-2 wrote:

>
Alexnb wrote:

>I don't get why yall are being so rude about this.

We're frustrated with your apparent inability to understand anything
we're saying.

>My problem is this; the
path, as a variable conflicts with other characters in the path, creating
escape characters I don't want, so I need a way to send the string to the
os.startfile () in raw, or, with all the backslashes doubled.

No, no, no, no, NO! That is not your problem! You are drawing unfounded
conclusions from the fact that you had to double up backslashes when the
filename came from a string literal. The situation is entirely different
when the filename comes from user input. No doubling up of backslashes
is necessary when the filename comes from user input. TRUST ME!

For simplicity, start with this code to convince yourself:

import os
filename = raw_input("Plea se enter a filename: ")
os.startfile(fi lename)

Once you get that to work, replace raw_input with a function that gets
the filename from your GUI.

Hope this helps,

--
Carsten Haese
http://informixdb.sourceforge.net
--
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[Ethan Furman]

Alexnb wrote:

Haha, okay well sorry that I was being so stupid, but I get it now

and I apoligize for causing you all the frustration. But I did get it to

work finally.