Re: Socket and cycle problem

[Jean-Paul Calderone]

On Mon, 12 May 2008 08:34:07 -0700 (PDT), pe********@gmai l.com wrote:

>Hello,
I am beginner but so I need help. I have small script for receive data
from port 3883, but it print only once.

import socket

HOST = 'localhost'
PORT = 3883
s = socket.socket(s ocket.AF_INET, socket.SOCK_STR EAM)
s.connect((HOS T, PORT))
data = s.recv(2048)
s.close()
print 'receive data from server:', `data`

So I try to write cycle to this script, like this:

import socket

HOST = 'localhost'
PORT = 3883
s = socket.socket(s ocket.AF_INET, socket.SOCK_STR EAM)
while 1:
s.connect((HOST , PORT))
data = s.recv(2048)
s.close()
print 'receive data from server:', `data`

But Python reporting:

Traceback (most recent call last):
File "C:\Documen ts and Settings\poupa\ Plocha\TCP3.py" , line 7, in
<module>
s.connect((HOST , PORT))
File "<string>", line 1, in connect
File "C:\Python25\li b\socket.py", line 141, in _dummy
raise error(EBADF, 'Bad file descriptor')
error: (9, 'Bad file descriptor')

Where is the mistake? I dont know.

You cannot reconnect a socket. You need to create a new one for each
connection. It's also almost certainly the case that the way you are
receiving data is incorrect. There is no guarantee that you will get
2048 bytes from socket.recv(204 8). It isn't even guaranteed that all
the bytes written to the socket by the peer will be returned by such
a call. Instead, you need a framing protocol to determine when all
data has been received. For example, you might length prefix the
data, or you might insert a delimiter (or a terminator) at the end. Or
if there is exactly one message to receive, then you should just read
until the recv call returns '', indicating EOF.

Jean-Paul

[petr.poupa]

On 12 Kvì, 17:54, Jean-Paul Calderone <exar...@divmod .comwrote:

On Mon, 12 May 2008 08:34:07 -0700 (PDT), petr.po...@gmai l.com wrote:

Hello,
I am beginner but so I need help. I have small script for receive data
from port 3883, but it print only once.

import socket

HOST = 'localhost'
PORT = 3883
s = socket.socket(s ocket.AF_INET, socket.SOCK_STR EAM)
s.connect((HOST , PORT))
data = s.recv(2048)
s.close()
print 'receive data from server:', `data`

So I try to write cycle to this script, like this:

import socket

HOST = 'localhost'
PORT = 3883
s = socket.socket(s ocket.AF_INET, socket.SOCK_STR EAM)
while 1:
s.connect((HOST , PORT))
data = s.recv(2048)
s.close()
print 'receive data from server:', `data`

But Python reporting:

Traceback (most recent call last):
File "C:\Documen ts and Settings\poupa\ Plocha\TCP3.py" , line 7, in
<module>
s.connect((HOST , PORT))
File "<string>", line 1, in connect
File "C:\Python25\li b\socket.py", line 141, in _dummy
raise error(EBADF, 'Bad file descriptor')
error: (9, 'Bad file descriptor')

Where is the mistake? I dont know.

You cannot reconnect a socket. You need to create a new one for each
connection. It's also almost certainly the case that the way you are
receiving data is incorrect. There is no guarantee that you will get
2048 bytes from socket.recv(204 8). It isn't even guaranteed that all
the bytes written to the socket by the peer will be returned by such
a call. Instead, you need a framing protocol to determine when all
data has been received. For example, you might length prefix the
data, or you might insert a delimiter (or a terminator) at the end. Or
if there is exactly one message to receive, then you should just read
until the recv call returns '', indicating EOF.

Jean-Paul

ok thanks, but I am true greenhorn, so you think that the best way is
write new script?
Could you send me code if it isnt long, becase I have no idea and
unfortunately time as well.

Petr
Petr