comparing dictionaries

[brad]

I want to compare two dicts that should have identical info just in a
different data structure. The first dict's contents look like this. It
is authoritative.. . I know for sure it has the correct key value pairs:

{'001' : '01'}

The second dict's contents are like this with a tuple instead of a
string for the key:

{('This is one', '001'): '01'}

Pseudo Code:
for key, value in first_dict.iter items():
# How do I do the following line?
if key not in second_dict or if it is, but has has the wrong value,
then let me know

[cokofreedom]

On May 7, 4:08 pm, brad <byte8b...@gmai l.comwrote:

I want to compare two dicts that should have identical info just in a
different data structure. The first dict's contents look like this. It
is authoritative.. . I know for sure it has the correct key value pairs:

{'001' : '01'}

The second dict's contents are like this with a tuple instead of a
string for the key:

{('This is one', '001'): '01'}

Pseudo Code:
for key, value in first_dict.iter items():
# How do I do the following line?
if key not in second_dict or if it is, but has has the wrong value,
then let me know

Well

for k, v in first_dict.item s():
if k not in second_dict or k in second_dict and k[v] !=
second_dict[k]:
let you know?

[Carsten Haese]

brad wrote:

I want to compare two dicts that should have identical info just in a
different data structure. The first dict's contents look like this. It
is authoritative.. . I know for sure it has the correct key value pairs:

{'001' : '01'}

The second dict's contents are like this with a tuple instead of a
string for the key:

{('This is one', '001'): '01'}

It looks like extracting key[1] from each key of the second dictionary
should yield the keys of the first dictionary. If that is the case, then
the following should do it:

d1 = {'001':'01', '002':'02'}
d2 = {('This is one', '001'): '01', ('This is two', '002'): '02'}

if d1 == dict( zip( (k[1] for k in d2.keys()), d2.values() ) ):
print "They're 'equal'."

HTH,

--
Carsten Haese
http://informixdb.sourceforge.net

[Arnaud Delobelle]

brad <by*******@gmai l.comwrites:

I want to compare two dicts that should have identical info just in a
different data structure. The first dict's contents look like this. It
is authoritative.. . I know for sure it has the correct key value
pairs:

{'001' : '01'}

-refdict

>
The second dict's contents are like this with a tuple instead of a
string for the key:

{('This is one', '001'): '01'}

-multidict

>
Pseudo Code:
for key, value in first_dict.iter items():
# How do I do the following line?
if key not in second_dict or if it is, but has has the wrong value,
then let me know

I think it's best to iterate over items of the second dictionary
first. I am assuming that a key can be repeated in the second
dictionary, otherwise it could be a bit simpler:

missing_keys = set(first_dict)
for keys, val in second_dict.ite ritems():
for key in keys:
missing_keys.di scard(key)
if first_dict.get( key, val) != val:
print "wrong value for", key, 'in', keys
if missing_keys:
print 'some keys are missing:', ',',join(remain ing)

--
Arnaud

[Miki]

Hello,

I want to compare two dicts that should have identical info just in a
different data structure. The first dict's contents look like this. It
is authoritative.. . I know for sure it has the correct key value pairs:

{'001' : '01'}

The second dict's contents are like this with a tuple instead of a
string for the key:

{('This is one', '001'): '01'}

Pseudo Code:
for key, value in first_dict.iter items():
* *# How do I do the following line?
* *if key not in second_dict or if it is, but has has the wrong value,
then let me know

def cmp_dicts(first , second):
return sorted(first.it eritems()) == \
sorted(((k[1], v) for k, v in second.iteritem s()))

Google for DSU (Decorate-Sort-Undecorate)

HTH,
--
Miki <mi*********@gm ail.com>
http://pythonwise.blogspot.com

[Terry Reedy]

"Miki" <mi*********@gm ail.comwrote in message
news:ad******** *************** ***********@b9g 2000prh.googleg roups.com...
Hello,

I want to compare two dicts that should have identical info just in a
different data structure. The first dict's contents look like this. It
is authoritative.. . I know for sure it has the correct key value pairs:

{'001' : '01'}

The second dict's contents are like this with a tuple instead of a
string for the key:

{('This is one', '001'): '01'}

Pseudo Code:
for key, value in first_dict.iter items():
# How do I do the following line?
if key not in second_dict or if it is, but has has the wrong value,
then let me know

Does this work for you?

for key,value in second_dict.ite ritems():
try:
if first_dict[key(1)] == value:
return True
else:
return False:
except KeyError:
return False

tjr