I'm trying to supply parameters to a function that is called at a
later time as in the code below:
llist = []
for item in range(5):
llist.append(la mbda: func(item))
def func(item):
print item
for thing in llist:
thing()
which produces the result
IDLE 1.2.1
>>============= =============== ==== RESTART =============== =============== ==
<function <lambdaat 0xb716356c>
<function <lambdaat 0xb71635a4>
<function <lambdaat 0xb71635dc>
<function <lambdaat 0xb7163614>
<function <lambdaat 0xb716364c>
>>============= =============== ==== RESTART =============== =============== ==
4
4
4
4
4
>>>
How can one allocate a different parameter to each instance of the
function rather than all of them getting the final value of the loop? 4 1009
wyleu wrote:
I'm trying to supply parameters to a function that is called at a
later time as in the code below:
llist = []
for item in range(5):
llist.append(la mbda: func(item))
def func(item):
print item
for thing in llist:
thing()
which produces the result
IDLE 1.2.1
>>>============ =============== ===== RESTART ============ =============== =====
<function <lambdaat 0xb716356c>
<function <lambdaat 0xb71635a4>
<function <lambdaat 0xb71635dc>
<function <lambdaat 0xb7163614>
<function <lambdaat 0xb716364c>
>>>============ =============== ===== RESTART ============ =============== =====
4
4
4
4
4
>>>>
How can one allocate a different parameter to each instance of the
function rather than all of them getting the final value of the loop?
That's a FAQ. Python creates a closure for you that will retain the last
value bound. To prevent that, you need to create a named paramter like
this:
lambda item=item: func(item)
That will bind the current item value at the lambda creation time.
Diez
One way :
>>from functools import partial def func(item) : print item
>>llist = [partial(func,it em) for item in range(5)] for thing in llist : thing()
0
1
2
3
4
wyleu wrote:
I'm trying to supply parameters to a function that is called at a
later time as in the code below:
llist = []
for item in range(5):
llist.append(la mbda: func(item))
def func(item):
print item
for thing in llist:
thing()
which produces the result
IDLE 1.2.1
>>>============ =============== ===== RESTART =============== =============== ==
<function <lambdaat 0xb716356c>
<function <lambdaat 0xb71635a4>
<function <lambdaat 0xb71635dc>
<function <lambdaat 0xb7163614>
<function <lambdaat 0xb716364c>
>>>============ =============== ===== RESTART =============== =============== ==
4
4
4
4
4
How can one allocate a different parameter to each instance of the
function rather than all of them getting the final value of the loop?
Boris Borcic wrote:
One way :
>>from functools import partial
>>def func(item) : print item
>>llist = [partial(func,it em) for item in range(5)]
>>for thing in llist : thing()
0
1
2
3
4
Another way:
class Func(object):
def __init__(self, item):
self.item = item
def __call__(self):
print self.item
llist = [Func(item) for item in range(5)]
for thing in llist: thing()
On May 6, 5:17*am, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:
wyleu wrote:
I'm trying to supply parameters to a function that is called at a
later time as in the code below:
llist = []
for item in range(5):
* * llist.append(la mbda: func(item))
def func(item):
* * print item
for thing in llist:
* * thing()
which produces the result
IDLE 1.2.1
>>============= =============== ==== RESTART ============= =============== ====
<function <lambdaat 0xb716356c>
<function <lambdaat 0xb71635a4>
<function <lambdaat 0xb71635dc>
<function <lambdaat 0xb7163614>
<function <lambdaat 0xb716364c>
>>============= =============== ==== RESTART ============= =============== ====
4
4
4
4
4
How can one allocate a different parameter to each instance of the
function rather than all of them getting the final value of the loop?
That's a FAQ. Python creates a closure for you that will retain the last
value bound. To prevent that, you need to create a named paramter like
this:
lambda item=item: func(item)
That will bind the current item value at the lambda creation time.
Diez- Hide quoted text -
- Show quoted text -
I am getting lambda creation-time bindings on 2.5.
>>g= [ lambda h= i: h for i in range( 10 ) ] [ e( ) for e in g ]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>g= [ lambda: i for i in range( 10 ) ] [ e( ) for e in g ]
[9, 9, 9, 9, 9, 9, 9, 9, 9, 9] This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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