Recursive function won't compile

[bc1891]

#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):
if(n>1):
return n*RecursiveFact (n-1)
else:
return 1

fact = RecursiveFact(3 1)
print fact

fact = "End of program"
print fact
.......but yet it still gives the right answer. How is this possible?

[ajaksu]

On Apr 2, 5:23*pm, bc1...@googlema il.com wrote:

#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):
* * if(n>1):
* * * * return n*RecursiveFact (n-1)
* * else:
* * * * return 1

fact = RecursiveFact(3 1)
print fact

The output is 822283865417792 281772556288000 0000 and is correct. But
the "#include"s tell me you're a bit confused. Have you tried running
"python yourscript.py" (where "yourscript .py" is the filename you
saved the above program to)?

HTH,
Daniel

[dj3vande]

In article <be************ *************** *******@u36g200 0prf.googlegrou ps.com>,
<bc****@googlem ail.comwrote:

(Subject: Recursive function won't compile)

>#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):

>......but yet it still gives the right answer. How is this possible?

Possibly because it gives the right answer in a different language than
it fails to compile in?
dave

--
Dave Vandervies dj3vande at eskimo dot com
A violent rewrite could produce something worthwhile; as it is you need enough
experience to not need the book to be able to read it. Well, that makes sense
to me, anyhow. --CBFalconer in comp.lang.c

[Diez B. Roggisch]

bc****@googlema il.com schrieb:

#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):
if(n>1):
return n*RecursiveFact (n-1)
else:
return 1

fact = RecursiveFact(3 1)
print fact

fact = "End of program"
print fact
......but yet it still gives the right answer. How is this possible?

Given that you obviously don't use python, but some weird cross-breed
beteween python and C - who are we to judge the semantics of that chimera?

Diez

[Gary Herron]

bc****@googlema il.com wrote:

#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):
if(n>1):
return n*RecursiveFact (n-1)
else:
return 1

fact = RecursiveFact(3 1)
print fact

fact = "End of program"
print fact
......but yet it still gives the right answer. How is this possible?

Why not? What did you expect?

Hint:

The first two lines are comments to Python -- so are ignored.

The last two lines just print a string -- no problem there.

The recursive calculation is standard -- the extra set of parenthesis in
the if don't cause any problem.

So again please: Why are you surprised?

Gary Herron

[George Sakkis]

On Apr 2, 5:00 pm, "Diez B. Roggisch" <de...@nospam.w eb.dewrote:

bc1...@googlema il.com schrieb:

#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):
if(n>1):
return n*RecursiveFact (n-1)
else:
return 1

fact = RecursiveFact(3 1)
print fact

fact = "End of program"
print fact

......but yet it still gives the right answer. How is this possible?

Given that you obviously don't use python, but some weird cross-breed
beteween python and C - who are we to judge the semantics of that chimera?

Diez

Seems like a bad belated April Fool's day joke to me.

George

[Keith Thompson]

"Diez B. Roggisch" <de***@nospam.w eb.dewrites:

>#include <stdio.h>
#include <stdlib.h>

def RecursiveFact(n ):
if(n>1):
return n*RecursiveFact (n-1)
else:
return 1

fact = RecursiveFact(3 1)
print fact

fact = "End of program"
print fact
......but yet it still gives the right answer. How is this possible?

Given that you obviously don't use python, but some weird cross-breed
beteween python and C - who are we to judge the semantics of that
chimera?

What do you mean? Aren't these:

#include <stdio.h.
#include <stdlib.h>

perfectly valid comments in Python?

Followups redirected.

--
Keith Thompson (The_Other_Keit h) <ks***@mib.or g>
Nokia
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"