dividing list of numbers in to groups

[meggahertz]

Hello Everyone!

I need help with dividing a list of numbers in to groups of numbers that have constant difference between them. This constant number does not change it remains the same . e.g. 1000 in the following example:

Thank you in advance.

The list is:

List = [ 40000, 41000, 42000, 43000, 54000, 55000, 56000, 90000]

the routine i need should give me:

grp1 = [40000, 41000, 42000, 43000]
grp2 = [54000, 55000, 56000]
grp3 = [90000]

[hidrkannan]

Below code might work...but may not be a natural one...

import os
import sys
 
aList = [10,12,14,16]
 
const = 7
 
aList.sort()
 
minVal = min(aList)
maxVal = max(aList)
 
agroupDict = {}
count = 1
agroupDict[count] = [minVal]
aList.remove(minVal)
value = minVal + const
 
 
 
while value <= maxVal:
    if value in aList:
        agroupDict[count].append(value)
        aList.remove(value)
        value = value + const
    else:
        count = count + 1
        agroupDict[count] = []
        value = min(aList)
 
if value > maxVal:
    for tempVal in aList:
        count = count + 1
        agroupDict[count] = [tempVal]        
print agroupDict
 

SKN

[bvdet]

def group_nums(numlist, diff=1000):
    resultDict = {}
    idx = 0
    for i, num in enumerate(numlist):
        if i:
            if num - numlist[i-1] != diff:
                idx += 1
            resultDict.setdefault(idx, []).append(num)
        else:
            resultDict[idx] = [num, ]
    return resultDict
 
numlist = [40000, 41000, 42000, 43000, 54000, 55000, 56000, 90000]
dd = group_nums(numlist)
print dd.values()
dd = group_nums(numlist, 11000)
print dd.values()

Output:
>>> [[40000, 41000, 42000, 43000], [54000, 55000, 56000], [90000]]
[[40000], [41000], [42000], [43000, 54000], [55000], [56000], [90000]]
>>>