I'm really really newbie, almost no knowledge about python.
The problem I have is :
example) -
a = [ 1, 2, 3, 4, 5, 6, 7 ]
-
for n in a:
-
if a[n] < 4:
-
del a[n]
if I code like this, an error occurs, because the number of elements is changed.
so, what should I do to do this withour any error.
Is there any way to access list datas simultaneously?
6 1063
Rather than deleting items that fail the test, try copying the good'uns to a new list.
I'm really really newbie, almost no knowledge about python.
The problem I have is :
example) -
a = [ 1, 2, 3, 4, 5, 6, 7 ]
-
for n in a:
-
if a[n] < 4:
-
del a[n]
if I code like this, an error occurs, because the number of elements is changed.
so, what should I do to do this withour any error.
Is there any way to access list datas simultaneously?
I don't get what you are trying to do. You have a list of indexes (??) that you use to acces that same list? Is this what you want: -
a = range(1, 8) # generates a list like yours
-
new = []
-
for n in a:
-
if n < 4:
-
new.append(n)
-
Or you could use filter(): -
a = range(1, 8)
-
new = filter(lambda x: x < 4, a)
-
Or maybe a list comprehension is clearer: -
a = range(1, 8)
-
new = [n for n in a if n < 4]
-
bartonc 6,596
Recognized Expert Expert
I'm really really newbie, almost no knowledge about python.
The problem I have is :
example) -
a = [ 1, 2, 3, 4, 5, 6, 7 ]
-
for n in a:
-
if a[n] < 4:
-
del a[n]
if I code like this, an error occurs, because the number of elements is changed.
so, what should I do to do this withour any error.
Is there any way to access list datas simultaneously?
Our new friend, Strider1066, has a good suggestion.
For a quick copy of a simple list, use a "slice": -
>>> for i, item in enumerate(a[:]): # A "slice" from beginning to end
-
... if item < 4:
-
... del a[i]
-
...
-
>>> a
-
[2, 4, 6, 7]
-
>>>
Our new friend, Strider1066, has a good suggestion.
For a quick copy of a simple list, use a "slice": -
>>> for i, item in enumerate(a[:]): # A "slice" from beginning to end
-
... if item < 4:
-
... del a[i]
-
...
-
>>> a
-
[2, 4, 6, 7]
-
>>>
Are you sure that works? I mean, 2 is not greater than 4. It works with a.remove() but I get the same results like yours when I use del. I never actually use del. What does it do?
bartonc 6,596
Recognized Expert Expert
Are you sure that works? I mean, 2 is not greater than 4. It works with a.remove() but I get the same results like yours when I use del. I never actually use del. What does it do?
OOoooops! Can't rely on the index into a changing list.
Remove works because it doesn't rely on the index of the item. -
>>> a = [ 1, 2, 3, 4, 5, 6, 7 ]
-
>>> for item in a[:]: # A "slice" from beginning to end
-
... if item < 4:
-
... a.remove(item)
-
...
-
>>> a
-
[4, 5, 6, 7]
-
>>> a = [ 1, 2, 3, 4, 5, 6, 7 ]
-
>>> for item in a[:]: # A "slice" from beginning to end
-
... if item < 4 or item == 7:
-
... a.remove(item)
-
...
-
>>> a
-
[4, 5, 6]
-
>>>
Nice catch, my friend. Thank you.
Thank you everyone, it was wiser to copy and replace lists.
I'm going to like here. :) thx
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