How to execute a file outside module's namespace?

[Slawomir Nowaczyk]

Hello,

Let's say I have a module "emacs", defining function eexecfile(file) :

def eexecfile(file) :
# do other stuff
execfile(file,g lobals())
# do other stuff

Now, assume I have file test.py containing an assignment "x=1"

If I run python and do:

import emacs
emacs.eexecfile ("test.py")
print emacs.x # works, x was put in module namespace
print x # doesn't work, x is not defined in main script namespace

What is the best way to make "print x" work? Using the following:

import __main__
def eexecfile(file) :
# do other stuff
execfile(file, __main__.__dict __)
# do other stuff

seems to work, but it gives me a slightly uneasy feeling. Is this the
right way?

--
Best wishes,
Slawomir Nowaczyk
( Sl************* **@cs.lth.se )

Today advance is so rapid that even the astronauts who set foot on the
moon in 1969 had never seen a digital watch

[Angelo Zhou]

Slawomir Nowaczyk wrote:

Hello,

Let's say I have a module "emacs", defining function eexecfile(file) :

def eexecfile(file) :
# do other stuff
execfile(file,g lobals())
# do other stuff

Now, assume I have file test.py containing an assignment "x=1"

If I run python and do:

import emacs
emacs.eexecfile ("test.py")
print emacs.x # works, x was put in module namespace
print x # doesn't work, x is not defined in main script namespace

What is the best way to make "print x" work? Using the following:

import __main__
def eexecfile(file) :
# do other stuff
execfile(file, __main__.__dict __)
# do other stuff

seems to work, but it gives me a slightly uneasy feeling. Is this the
right way?

"from emacs import x" will expose x to the current namespace

[Angelo Zhou]

Slawomir Nowaczyk wrote:

Hello,

Let's say I have a module "emacs", defining function eexecfile(file) :

def eexecfile(file) :
# do other stuff
execfile(file,g lobals())
# do other stuff

Now, assume I have file test.py containing an assignment "x=1"

If I run python and do:

import emacs
emacs.eexecfile ("test.py")
print emacs.x # works, x was put in module namespace
print x # doesn't work, x is not defined in main script namespace

What is the best way to make "print x" work? Using the following:

import __main__
def eexecfile(file) :
# do other stuff
execfile(file, __main__.__dict __)
# do other stuff

seems to work, but it gives me a slightly uneasy feeling. Is this the
right way?

"from emacs import x" will expose x to the current namespace

[Slawomir Nowaczyk]

On Fri, 11 Aug 2006 01:23:14 +0800
Angelo Zhou <mz***@cs.hku.h kwrote:

#Slawomir Nowaczyk wrote:
# Hello,
#
# Let's say I have a module "emacs", defining function eexecfile(file) :
#
# def eexecfile(file) :
# # do other stuff
# execfile(file,g lobals())
# # do other stuff
#
# Now, assume I have file test.py containing an assignment "x=1"
#
# If I run python and do:
#
# import emacs
# emacs.eexecfile ("test.py")
# print emacs.x # works, x was put in module namespace
# print x # doesn't work, x is not defined in main script namespace
#
# What is the best way to make "print x" work? Using the following:
#
# import __main__
# def eexecfile(file) :
# # do other stuff
# execfile(file, __main__.__dict __)
# # do other stuff
#
# seems to work, but it gives me a slightly uneasy feeling. Is this the
# right way?
#
#>
#"from emacs import x" will expose x to the current namespace

True... but I do not know in advance what is the contents of test.py
file -- it could be "a=1" :) Sure, I could go over emacs.__dict__ and
expose everything except eexecfile, but that's even less satisfying
than the solution above.

Anyway, thanks for the suggestion.

--
Best wishes,
Slawomir Nowaczyk
( Sl************* **@cs.lth.se )

Zawinski's Law: "Every program attempts to expand until it can read mail.
Those programs which cannot so expand are replaced by ones which can."

[Piet van Oostrum]

>>>>Slawomir Nowaczyk <sl************ *******@student .lu.se(SN) wrote:

>SNHello,
SNLet's say I have a module "emacs", defining function eexecfile(file) :

>SNdef eexecfile(file) :
SN # do other stuff
SN execfile(file,g lobals())
SN # do other stuff

>SNNow, assume I have file test.py containing an assignment "x=1"

>SNIf I run python and do:

>SNimport emacs
SNemacs.eexecf ile("test.py")
SNprint emacs.x # works, x was put in module namespace
SNprint x # doesn't work, x is not defined in main script namespace

>SNWhat is the best way to make "print x" work? Using the following:

emacs.py:

def eexecfile(file, glob):
# do other stuff
execfile(file,g lob)

main:

import emacs
emacs.eexecfile ("test.py", globals())
print x

--
Piet van Oostrum <pi**@cs.uu.n l>
URL: http://www.cs.uu.nl/~piet [PGP 8DAE142BE17999C 4]
Private email: pi**@vanoostrum .org