Get path of a class

[Florian Lindner]

Hello,
how can I get the path of a class. I managed to do it with

c.__module__ + "." + c.__name__

but I'm sure there is a better way.

Thanks,

Florian

[Peter Hansen]

Florian Lindner wrote:

Hello,
how can I get the path of a class. I managed to do it with

c.__module__ + "." + c.__name__

but I'm sure there is a better way.

Please define what you mean by "path" (and how you hope to make use of
this information).

Generally a module has a "path" (i.e. a location where it can be loaded
from the file system) but classes are merely created by "class"
statements within a module. There is no one-to-one match with files,
and in fact no requirement that a class even be traceable directly to
statements in a source file.

-Peter

[Marc 'BlackJack' Rintsch]

In <11************ **********@g43g 2000cwa.googleg roups.com>, Florian
Lindner wrote:

Hello,
how can I get the path of a class. I managed to do it with

c.__module__ + "." + c.__name__

but I'm sure there is a better way.

How about using the `inspect` module::

In [33]: import inspect, zipfile

In [34]: inspect.getsour cefile(zipfile. ZipInfo)
Out[34]: '/usr/lib/python2.4/zipfile.py'

Ciao,
Marc 'BlackJack' Rintsch