Problem with exec

[Justus Schwabedal]

I'm trying to parallise with python. Specifically I'm sending code to
the processes and let them exec this code (in ascii form). However I
ran into a problem with Namespaces (I think) which I do not understand.

Here's what I do first:
---------------------------------------
bash-3.2$ cat execBug.py
#! /usr/bin/python
header="""
from scipy import randn
def f():
return randn()
"""
exec header
print "f() =",f()

bash-3.2$ ./execBug.py
f() = 0.633306324515
it est: it works.
However when I do this:

bash-3.2$ cat execBug2.py
#! /usr/bin/python
header="""
from scipy import randn
def f():
return randn()
"""
def g():
exec header
return f()
print "g() =",g()
bash-3.2$ ./execBug2.py
g() =
Traceback (most recent call last):
File "./execBug2.py", line 10, in <module>
print "g() =",g()
File "./execBug2.py", line 9, in g
return f()
File "<string>", line 4, in f
NameError: global name 'randn' is not defined
bash-3.2$ ???

I get this global name error. I can fix it with adding some line like
"global randn" but I don't want to do this. I want to do exactly what
I wrote: Import the function scipy.randn in the local namespace of the
function "g" so that "return f()" makes sense. Can anybody help me out?
Yours Justus

[alitosis]

On Mar 14, 9:47 am, Justus Schwabedal <justus.schwabe [e-mail]>
wrote:
[snipped]

However when I do this:

bash-3.2$ cat execBug2.py
#! /usr/bin/python
header="""
from scipy import randn
def f():
return randn()
"""
def g():
exec header
return f()
print "g() =",g()
bash-3.2$ ./execBug2.py
g() =
Traceback (most recent call last):
File "./execBug2.py", line 10, in <module>
print "g() =",g()
File "./execBug2.py", line 9, in g
return f()
File "<string>", line 4, in f
NameError: global name 'randn' is not defined
bash-3.2$ ???

I get this global name error. I can fix it with adding some line like
"global randn" but I don't want to do this. I want to do exactly what I wrote: Import the function scipy.randn in the local namespace of the

function "g" so that "return f()" makes sense. Can anybody help me out?
Yours Justus

Maybe using an explicit namespace is good enough for your needs:

#! /usr/bin/python
header="""
from scipy import randn
def f():
return randn()
"""
def g():
n = {}
exec header in n
return n['f']()
print "g() =",g()
(i don't understand the issues, but I can cut-and-paste with the best
of them)

[Justus Schwabedal]

On Mar 14, 2008, at 4:41 AM, al******@gmail. com wrote:

On Mar 14, 9:47 am, Justus Schwabedal <justus.schwabe [e-mail]>
wrote:
[snipped]

>However when I do this:

bash-3.2$ cat execBug2.py
#! /usr/bin/python
header="""
from scipy import randn
def f():
return randn()
"""
def g():
exec header
return f()
print "g() =",g()
bash-3.2$ ./execBug2.py
g() =
Traceback (most recent call last):
File "./execBug2.py", line 10, in <module>
print "g() =",g()
File "./execBug2.py", line 9, in g
return f()
File "<string>", line 4, in f
NameError: global name 'randn' is not defined
bash-3.2$ ???

I get this global name error. I can fix it with adding some line like
"global randn" but I don't want to do this. I want to do exactly
what I wrote: Import the function scipy.randn in the local
namespace of the

function "g" so that "return f()" makes sense. Can anybody help me
out?
Yours Justus

Maybe using an explicit namespace is good enough for your needs:

#! /usr/bin/python
header="""
from scipy import randn
def f():
return randn()
"""
def g():
n = {}
exec header in n
return n['f']()
print "g() =",g()
(i don't understand the issues, but I can cut-and-paste with the best
of them)
--
http://mail.python.org/mailman/listinfo/python-list

That's what I was looking for: It's probably even a faster solution
than declaring all the imports global, isn't it?