newby question: Splitting a string - separator

[Thomas Liesner]

Hi all,

i am having a textfile which contains a single string with names.
I want to split this string into its records an put them into a list.
In "normal" cases i would do something like:

#!/usr/bin/python
inp = open("file")
data = inp.read()
names = data.split()
inp.close()

The problem is, that the names contain spaces an the records are also
just seprarated by spaces. The only thing i can rely on, ist that the
recordseparator is always more than a single whitespace.

I thought of something like defining the separator for split() by using
a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

TIA,
Tom

[Michael Spencer]

Thomas Liesner wrote:

Hi all,

i am having a textfile which contains a single string with names.
I want to split this string into its records an put them into a list.
In "normal" cases i would do something like:

#!/usr/bin/python
inp = open("file")
data = inp.read()
names = data.split()
inp.close()

The problem is, that the names contain spaces an the records are also
just seprarated by spaces. The only thing i can rely on, ist that the
recordseparator is always more than a single whitespace.

I thought of something like defining the separator for split() by using
a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

TIA,
Tom

\s+ gives one or more, you need \s{2,} for two or more:

import re
re.split("\s{2, }","Guido van Rossum Tim Peters Thomas Liesner") ['Guido van Rossum', 'Tim Peters', 'Thomas Liesner']

Michael

[Noah]

Thomas Liesner wrote:

...
The only thing i can rely on, ist that the
recordseparator is always more than a single whitespace.

I thought of something like defining the separator for split() by using
a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

For your split regex you could say
"\s\s+"
or
"\s{2,}"

This should work for you:
YOUR_SPLIT_LIST = re.split("\s{2, }", YOUR_STRING)

Yours,
Noah

[Jim]

Hi Tom,

a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

For more than one, I'd use

\s\s+

-Jim

[James Stroud]

Thomas Liesner wrote:

Hi all,

i am having a textfile which contains a single string with names.
I want to split this string into its records an put them into a list.
In "normal" cases i would do something like:

#!/usr/bin/python
inp = open("file")
data = inp.read()
names = data.split()
inp.close()

The problem is, that the names contain spaces an the records are also
just seprarated by spaces. The only thing i can rely on, ist that the
recordseparator is always more than a single whitespace.

I thought of something like defining the separator for split() by using
a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

TIA,
Tom

The one I like best goes like this:

py> data = "Guido van Rossum Tim Peters Thomas Liesner"
py> names = [n for n in data.split() if n]
py> names
['Guido', 'van', 'Rossum', 'Tim', 'Peters', 'Thomas', 'Liesner']

I think it is theoretically faster (and more pythonic) than using regexes.

James

[Kent Johnson]

James Stroud wrote:

The one I like best goes like this:

py> data = "Guido van Rossum Tim Peters Thomas Liesner"
py> names = [n for n in data.split() if n]
py> names
['Guido', 'van', 'Rossum', 'Tim', 'Peters', 'Thomas', 'Liesner']

I think it is theoretically faster (and more pythonic) than using regexes.

Unfortunately it gives the wrong result.

Kent

[Tim Peters]

[James Stroud]

The one I like best goes like this:

py> data = "Guido van Rossum Tim Peters Thomas Liesner"
py> names = [n for n in data.split() if n]
py> names
['Guido', 'van', 'Rossum', 'Tim', 'Peters', 'Thomas', 'Liesner']

I think it is theoretically faster (and more pythonic) than using regexes.

[Kent Johnson] Unfortunately it gives the wrong result.

Still, it gets extra points for being such a pleasing example ;-)

[bonono]

Thomas Liesner wrote:

Hi all,

i am having a textfile which contains a single string with names.
I want to split this string into its records an put them into a list.
In "normal" cases i would do something like:

#!/usr/bin/python
inp = open("file")
data = inp.read()
names = data.split()
inp.close()

The problem is, that the names contain spaces an the records are also
just seprarated by spaces. The only thing i can rely on, ist that the
recordseparator is always more than a single whitespace.

I thought of something like defining the separator for split() by using
a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

Can I just use "two space" as the seperator ?

[ x.strip() for x in data.split(" ") ]

[James Stroud]

Kent Johnson wrote:

James Stroud wrote:

The one I like best goes like this:

py> data = "Guido van Rossum Tim Peters Thomas Liesner"
py> names = [n for n in data.split() if n]
py> names
['Guido', 'van', 'Rossum', 'Tim', 'Peters', 'Thomas', 'Liesner']

I think it is theoretically faster (and more pythonic) than using
regexes.

Unfortunately it gives the wrong result.

Kent

Just an example. Here is the "correct version":
names = [n for n in data.split(" ") if n]

James

[Michael Spencer]

bo****@gmail.co m wrote:

Thomas Liesner wrote:

Hi all,

i am having a textfile which contains a single string with names.
I want to split this string into its records an put them into a list.
In "normal" cases i would do something like:

#!/usr/bin/python
inp = open("file")
data = inp.read()
names = data.split()
inp.close()

The problem is, that the names contain spaces an the records are also
just seprarated by spaces. The only thing i can rely on, ist that the
recordseparator is always more than a single whitespace.

I thought of something like defining the separator for split() by using
a regex for "more than one whitespace". RegEx for whitespace is \s, but
what would i use for "more than one"? \s+?

Can I just use "two space" as the seperator ?

[ x.strip() for x in data.split(" ") ]

If you like, but it will create dummy entries if there are more than two spaces:

data = "Guido van Rossum Tim Peters Thomas Liesner"
[ x.strip() for x in data.split(" ") ] ['Guido van Rossum', 'Tim Peters', '', 'Thomas Liesner']

You could add a condition to the listcomp:
[name.strip() for name in data.split(" ") if name] ['Guido van Rossum', 'Tim Peters', 'Thomas Liesner']

but what if there is some other whitespace character?
data = "Guido van Rossum Tim Peters \t Thomas Liesner"
[name.strip() for name in data.split(" ") if name] ['Guido van Rossum', 'Tim Peters', '', 'Thomas Liesner']
perhaps a smarter condition?
[name.strip() for name in data.split(" ") if name.strip(" \t")] ['Guido van Rossum', 'Tim Peters', 'Thomas Liesner']

but this is beginning to feel like hard work.
I think this is a case where it's not worth the effort to try to avoid the regexp
import re
re.split("\s{2, }",data) ['Guido van Rossum', 'Tim Peters', 'Thomas Liesner']

Michael