Hi-
I just discovered this: -1 // 12
-1 1 // 12
0
I thought that -1 // 12 would be 0 also. I'm writing a simple monthly
date class and i need (-1,2001) to be translated to (11,2000). Any ideas? 7  2641 
"Matthew Wilson" <mw*****@sarcas tic-horse.com> writes: Hi-
I just discovered this:
-1 // 12 -1 1 // 12 0
I thought that -1 // 12 would be 0 also.
Why did you think that? Dividing -1 by 12 gives -1, with a remainder
of 11: -1*12 + 11 == -1.
I'm writing a simple monthly date class and i need (-1,2001) to be
translated to (11,2000). Any ideas?
def norm_month(mont h, year):
delta_year, month = divmod(month, 12)
return month, year+delta_year
print norm_month(-1, 2001)
Regards,
Martin
That definitely seems wrong to me, even though it is a correct "floor"
function.
I was given the impression that (int // int) was going to be the replacement
for (int / int) when (int / int) is changed to return a float, but -1/12 now
gives 0, not -1, so (int // int) is not a replacement for (int / int).
"Matthew Wilson" <mw*****@sarcas tic-horse.com> wrote in message
news:ma******** *************** ***********@pyt hon.org... Hi-
I just discovered this:
-1 // 12 -1 1 // 12 0
I thought that -1 // 12 would be 0 also. I'm writing a simple monthly
date class and i need (-1,2001) to be translated to (11,2000). Any ideas?
oops -- ignore that last post -- i was totally wrong
"Mark Hahn" <ma**@hahnca.co m> wrote in message
news:HWjfb.5187 $hp5.1152@fed1r ead04... That definitely seems wrong to me, even though it is a correct "floor"
function.
I was given the impression that (int // int) was going to be the
replacement for (int / int) when (int / int) is changed to return a float, but -1/12
now gives 0, not -1, so (int // int) is not a replacement for (int / int).
"Matthew Wilson" <mw*****@sarcas tic-horse.com> wrote in message
news:ma******** *************** ***********@pyt hon.org... Hi-
I just discovered this:
>> -1 // 12
-1>> 1 // 12
0>>
I thought that -1 // 12 would be 0 also. I'm writing a simple monthly
date class and i need (-1,2001) to be translated to (11,2000). Any
ideas?
Matthew Wilson wrote: I thought that -1 // 12 would be 0 also. I'm writing a simple monthly
date class and i need (-1,2001) to be translated to (11,2000). Any
ideas?
Luckily for you, Python integer division does the right thing. You
*want* -1 // 12 to be -1 for your application.
def normalize_date( month, year):
return (month % 12, year + month // 12)
normalize_date(-1, 2001) # Returns (11, 2000)
'normalize_date ' as given assumes 'month' is in the range from 0 to 11; use
this if your months are in the range from 1 to 12:
def normalize_date( month, year):
return ((month - 1) % 12 + 1, year + (month - 1) // 12)
--
Rainer Deyke - ra*****@eldwood .com - http://eldwood.com
Mark> I was given the impression that (int // int) was going to be the
Mark> replacement for (int / int) when (int / int) is changed to return
Mark> a float, but -1/12 now gives 0, not -1, so (int // int) is not a
Mark> replacement for (int / int). from __future__ import division
-1/12
-0.0833333333333 33329 -1//12
-1
Skip
"Matthew Wilson" <mw*****@sarcas tic-horse.com> wrote in message news:<ma******* *************** ************@py thon.org>... Hi-
I just discovered this:
-1 // 12 -1 1 // 12 0
I thought that -1 // 12 would be 0 also. I'm writing a simple monthly
date class and i need (-1,2001) to be translated to (11,2000). Any ideas?
Maybe the following could help: def normalize_date( month,year):
.... return (((month+11) % 12)+1,year+((mo nth-1)/12))
.... normalize_date( 1,2003)
(1, 2003) normalize_date( 12,2003)
(12, 2003) normalize_date( 0,2003)
(12, 2002) normalize_date(-1,2003)
(11, 2002) normalize_date( 13,2003)
(1, 2004)
Regards
Peter
"Matthew Wilson" <mw*****@sarcas tic-horse.com> wrote in message news:<ma******* *************** ************@py thon.org>... Hi-
I just discovered this:
-1 // 12 -1 1 // 12 0
I thought that -1 // 12 would be 0 also. I'm writing a simple monthly
date class and i need (-1,2001) to be translated to (11,2000). Any ideas?
-1 % 12
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