batch mkdir using a file list

[DataSmash]

Hello,
I think I've tried everything now and can't figure out how to do it.
I want to read in a text list from the current directory,
and for each line in the list, make a system directory for that name.

My text file would look something like this:
1144
1145
1146
1147

I simply want to create these 4 directories.
It seems like something like the following
code should work, but it doesn't.

import os

file = open("list.txt" , "r")
read = file.read()
print "Creating directory " + str(read)
os.mkdir(str(re ad))

Appreciate any help you can give!
R.D. Harles

[Fredrik Lundh]

DataSmash <rd*@new.rr.com > wrote

I think I've tried everything now and can't figure out how to do it.
I want to read in a text list from the current directory,
and for each line in the list, make a system directory for that name.

My text file would look something like this:
1144
1145
1146
1147

I simply want to create these 4 directories.
It seems like something like the following
code should work, but it doesn't.

import os

file = open("list.txt" , "r")
read = file.read()
print "Creating directory " + str(read)
os.mkdir(str(re ad))

read() returns *all* text in the file as a single string, but you
really want to process each line for itself. try this:

for name in open("list.txt" ):
name = name.strip() # get rid of extra whitespace
os.mkdir(name)

</F>

[Jeremy Jones]

DataSmash wrote:

Hello,
I think I've tried everything now and can't figure out how to do it.
I want to read in a text list from the current directory,
and for each line in the list, make a system directory for that name.

My text file would look something like this:
1144
1145
1146
1147

I simply want to create these 4 directories.
It seems like something like the following
code should work, but it doesn't.

import os

file = open("list.txt" , "r")
read = file.read()
print "Creating directory " + str(read)
os.mkdir(str(r ead))

Appreciate any help you can give!
R.D. Harles

Untested code:

import os
for line in open("list.txt" , "r"):
os.mkdir(line)
- JMJ

[mensanator]

Jeremy Jones wrote:

DataSmash wrote:

Hello,
I think I've tried everything now and can't figure out how to do it.
I want to read in a text list from the current directory,
and for each line in the list, make a system directory for that name.

My text file would look something like this:
1144
1145
1146
1147

I simply want to create these 4 directories.
It seems like something like the following
code should work, but it doesn't.

import os

file = open("list.txt" , "r")
read = file.read()
print "Creating directory " + str(read)
os.mkdir(str(r ead))

Appreciate any help you can give!
R.D. Harles
Untested code:

import os
for line in open("list.txt" , "r"):
os.mkdir(line)

That won't work (in Windows at least) because you have
to remove the "\n" from the line before you pass it to
os.mkdir.



- JMJ

[DataSmash]

I am using bash shell on windows and I'm getting the error:
TypeError: loop over non-sequence

Is there any way around not messing with the text file.
I want to batch generate the text lists as well.

Thanks!

[DataSmash]

OR...if python can't handle this type of text file,
what do I need to do to remove the "\n" from the file?

[Peter Otten]

DataSmash wrote:

I am using bash shell on windows and I'm getting the error:
TypeError: loop over non-sequence
Use open(filename). readlines() instead of open(filename) or switch to a
current Python version.
OR...if python can't handle this type of text file,
what do I need to do to remove the "\n" from the file?

line.strip() removes all leading and trailing whitespace (not just "\n")
from the line string.

import os
for line in open("list.txt" ).readlines():
directory = line.strip()
os.mkdir(direct ory)

Peter

[DataSmash]

Awesome! That worked!
Much thanks to Peter and all of you who took the time to answer my
question.
R.D.