easy float question just eludes me

[nephish]

Hullo all !

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)
but i need it to display the .00 even if it does not have a .00 value
like this
if Var is 50, i need to display .50 instead of just .5

i know there is an easy way to do this.
thanks

[Simon Brunning]

On 28 Jul 2005 06:39:32 -0700, ne*****@xit.net <ne*****@xit.ne t> wrote:

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)
but i need it to display the .00 even if it does not have a .00 value
like this
if Var is 50, i need to display .50 instead of just .5

import decimal as dec
dec.Decimal('25 0.00')/100

Decimal("2.50")

--
Cheers,
Simon B,
si***@brunningo nline.net,
http://www.brunningonline.net/simon/blog/

[nephish]

way cool, outta work out just fine

On 07/28/2005 08:48:27 AM, Simon Brunning wrote:

On 28 Jul 2005 06:39:32 -0700, ne*****@xit.net <ne*****@xit.ne t>
wrote:

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)
but i need it to display the .00 even if it does not have a .00

value

like this
if Var is 50, i need to display .50 instead of just .5

import decimal as dec
dec.Decimal('25 0.00')/100

Decimal("2.50")

--
Cheers,
Simon B,
si***@brunningo nline.net,
http://www.brunningonline.net/simon/blog/

[Sergei Organov]

ne*****@xit.net writes:

Hullo all !

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)
but i need it to display the .00 even if it does not have a .00 value
like this
if Var is 50, i need to display .50 instead of just .5

i know there is an easy way to do this.

print "%.2f" % (50./100)

0.50

[nephish]

oops, i dont seem to have a module decimal
-shawn

On 07/28/2005 08:48:27 AM, Simon Brunning wrote:

On 28 Jul 2005 06:39:32 -0700, ne*****@xit.net <ne*****@xit.ne t>
wrote:

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)
but i need it to display the .00 even if it does not have a .00

value

like this
if Var is 50, i need to display .50 instead of just .5

import decimal as dec
dec.Decimal('25 0.00')/100

Decimal("2.50")

--
Cheers,
Simon B,
si***@brunningo nline.net,
http://www.brunningonline.net/simon/blog/

[Steve Holden]

ne*****@xit.net wrote:

Hullo all !

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)
but i need it to display the .00 even if it does not have a .00 value
like this
if Var is 50, i need to display .50 instead of just .5

i know there is an easy way to do this.
thanks

Play with this:

"%.2f"%0.5 '0.50' a = 50.0
("%.2f" % (a/100))[-3:] '.50'
I presume that a stays in the range 0 <= a < 100.
If not you will have to handle the integral digits as well with
something like
"%4.2f" % 3.1 '3.10' "%6.2f" % 3.1 ' 3.10'

regards
Steve
--
Steve Holden [phone] [phone]
Holden Web LLC http://www.holdenweb.com/

[Terry Reedy]

<ne*****@xit.ne t> wrote in message
news:11******** **************@ o13g2000cwo.goo glegroups.com.. .

Hullo all !

i have a real easy one here that isn't in my book.
i have a int number that i want to divide by 100 and display to two
decimal places.

like this float(int(Var)/100)

At present, int/int truncates, so this won't do what you want. Use
int/100.0 to get float you want. For output, use % formating operator with
f specification.

'%7.2f' % (50/100.0)

' 0.50'

Terry J. Reedy

[Dennis Lee Bieber]

On 28 Jul 2005 06:39:32 -0700, ne*****@xit.net declaimed the following
in comp.lang.pytho n:

like this float(int(Var)/100)
First problem -- you are (or were, the operators have been
changing in Python) doing an integer/integer divide which (used to)
returns an integer, and integers don't have fractional parts; and /then/
you are telling it to convert this integer result to a float.

You need to convert the division to floats before performing it:

i = 50
i/100 # integer/integer 0 float(i)/100 # convert to float/integer 0.5 i/100.0 # integer/float 0.5 but i need it to display the .00 even if it does not have a .00 value
like this
if Var is 50, i need to display .50 instead of just .5
Display is formatting, separate from computational usage...
"%7.2f" % (i/100.0) ' 0.50' "%.2f" % (float(i)/100)

'0.50'

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