A Call to PHP Function on INPUT field is not working

[Easytime]

Dear Pros,

I've written a php function script to check the a default value of a text field during an onFocus and onMouseOut events.
The default value of the text field is 'Search'.
When a user sets focus on the text field, the value should clear to empty string.
When the user removes focus and without entering a text, the value should be set back to 'Search'.
Else a $value variable should be assigned the value of the user input in the text field.
Please see the code below and help me out - cos, I am having problem calling the script on the input field. I'm not even sure whether the script is wrong or not...

<?php
function setValue()
   {
if (!empty($_REQUEST['qfront']) && $_REQUEST['qfront']=='Search')
   {
 
 $value=''; //$_REQUEST['qfront']="";
   }
   elseif (!empty($_REQUEST['qfront']) && $_REQUEST['qfront']!='Search')
   {
 $value=$_REQUEST['qfront'];
    }
   else //if (empty($_REQUEST['qfront'])
   {
$value='Search';
   }
return setValue();
}
?>
 
 

[Rabbit]

PHP is a server side language. It will not run on the client's computer. What you want to do is run something when the client takes a certain action, to do that, you need to use a client side language like Javascript.

[Easytime]

I have a WAMP installed on my computer. I use PHP to script other functions and they run. I develop my files on php and they run just because I have installed WAMP on my pc. It;s just that, I'm having problem figuring out where the code has a bug that does not allow it to run.

Pls kindly help me.
Thank you!

[Rabbit]

I didn't say PHP wouldn't run. But it will only run on your server. If you are trying to do something on the client's computer however, you will need to use a client side script like Javascript. onFocus and onMouseout events are client side events. Hence you need to use client side scripting. Like Javascript.