How to output data from array?

[apssiva]

Hi,

I am new for php. I don't know.... what to do? but i try to get data using "foreach($data as $key => $value), but i got error message "Warning: Invalid argument supplied for foreach()"

my code is below

$query = "SELECT meta_aps FROM sgc where nric = 'S9214548D'";
 
    $result = mysql_query($query) or die (mysql_error());
 
    $num = mysql_numrows($result);
 
 
 
        for ($i = 0; $i < $num; $i++) {
 
        $extra = mysql_result($result,$i);
 
    $serializedData = $extra;
 
    $data = @unserialize($serializedData);
 
    foreach($data as $key => $value){
        print_r($value);
 
    }
//print_r ($data);
echo '<br>';
 
  }
 

i got the output

Array ( [carer] => Soh Man was a student of (APS) from Jan 2007- Nov 2010 During her time in school, Soh Man managed to demonstrate care for her fellow classmates. She often took the initiative to help new students; she is a member of Boys Scout and was the class monitor. [story] => She has demonstrated her commitment and particicationable by carrying out tasks assigned to her diligently and responsibly. [other] => She adapts very well to unfamiliar environment easily. She is an honest and reliable person. ) 
 

But i want to display the output like below. pls help
Carer:
Soh Man was a student of (APS) from Jan 2007- Nov 2010 During her time in school, Soh Man managed to demonstrate care for her fellow classmates. She often took the initiative to help new students; she is a member of Boys Scout and was the class monitor.
Story:
She has demonstrated her commitment and particicationable by carrying out tasks assigned to her diligently and responsibly.
Others:
She adapts very well to unfamiliar environment easily. She is an honest and reliable person.

[Niheel]

So you've managed to get your data into an array.

To output it in the format you requested all you need to do is output different array variables.

In your case simple code like this:

?>
Career:
<?=data["carer"]?>
 
Story:
<?=$data["story"]?>
 
Others:
<?=data["others"]?>
 
<?php