mysql fetch array not iterating through the records

[BinaryBird]

Hi, i have a small script to display records from two tables. Table 1 keeps track of teams and table 2 keeps track of the members.

<?php
$dl = mysql_connect ("localhost","nitin_nick","test1234");
$db = mysql_select_db("nitin_registration",$dl);
 
echo "<table border='0' width='986' align='center' cellspacing='1' cellpadding='5'>";
echo "<tr>";
 
echo "<th>Team Name</th>";
echo "<th>Team Contact</th>";
echo "<th>Member Name</th>";
echo "<th>Member Email</th>";
echo "<th>Mobile Phone</th>";
echo "<th>College</th>";
echo "</tr>";
$result1="";
$result2="";
$query1 = "SELECT * FROM team ";
$q1_set = mysql_query($query1,$dl);
 
while ($result1 = mysql_fetch_array($q1_set)) {
   $team_id = $result1['id'];
   echo "<tr>";
   echo "<td>".$result1['name']."</td>";
   echo "<td>".$result1['contact']."</td>";
   echo "<td>".""."</td>";
   echo "<td>".""."</td>";
   echo "<td>".""."</td>";
   echo "<td>".""."</td>";
   echo "</tr>";
   $query2 = "SELECT * FROM member WHERE team_id={$team_id} LIMIT 3";
 
   $q2_set = mysql_query($query2,$dl) ;
 
   $result2 = mysql_fetch_array($q2_set);
     $count=0;
 
   while ($result2 && $count<3)  {   //The index of $result2 is not incrementing
        echo "<tr>";
        echo "<td>".""."</td>";
        echo "<td>".""."</td>";
        echo "<td>".$result2['name']."</td>";
        echo "<td>".$result2['email']."</td>";
        echo "<td>".$result2['phone']."</td>";
        echo "<td>".$result2['college']."</td>";
        echo "</tr>";
        $count++ ;
 
   } 
}
 
 
echo "</table>";
 
?>
 

The second query where i am trying to pull members with the team id, the result of mysql_fetch_array() is not incrementing the index of the array. When i run the script its goes into a infinite loop,( the second while loop) It just has the first record . Have i done something wrong here? Kindly help me out. Thanks.

[Dormilich]

yepp, you do your second loop inside the first loop, thus the variable of the first loop is not incremented, as long as the second loop didn’t finish.