Ereg specialists, I need your help

[Aphrael]

I would like a regular expression to do so:
Base:
<A HREF="somelink" maybesomthing="heretoo">linkface</A>
and I want:
(somelink) linkface
Is this possible ? If yes, how ?

And by the way, if anyone has a GOOD and CLEAR explanation about regular
expressions... please post it :-)

Aphrael, lost...
--
"La demande mondiale d’ordinateurs n’excédera pas cinq machines."
(Thomas Watson, Fondateur d'IBM, 1945)

[Aphrael]

Aphrael wrote:
[snip]
And to make it more complex, if possible (but I doubt that), if somelink
== linkface, i would like to display only linkface. Possible with
ereg_replace ? or preg_replace ?

Aphrael... wishing upon a PHPstar ;-)
--
"La demande mondiale d’ordinateurs n’excédera pas cinq machines."
(Thomas Watson, Fondateur d'IBM, 1945)

[Christopher Finke]

"Aphrael" <ap*****@isuisse.com> wrote in message
news:41********@news.bluewin.ch...

I would like a regular expression to do so:
Base:
<A HREF="somelink" maybesomthing="heretoo">linkface</A>
and I want:
(somelink) linkface
Is this possible ? If yes, how ?

Perhaps something like this:

$string = '<A HREF="somelink" maybesomthing="heretoo">linkface</A>';

$newstring = preg_replace("/<a href=\"(.*)\".*>(.*)</a>/Uis","(\\1) \\2",
$string);

Chris Finke

[Michael Fesser]

.oO(Aphrael)

Aphrael wrote:
[snip]
And to make it more complex, if possible (but I doubt that), if somelink
== linkface, i would like to display only linkface. Possible with
ereg_replace ? or preg_replace ?

Sure. ;)
The magic needed in this case is the modifier 'e'.

$text = '<A HREF="somelink" maybesomthing="heretoo">linkface</A>';
$pattern = '#<a href="(.+)".*>(.+)</a>#eisU';
$replace = '"$1" == "$2" ? "$1" : "($1) $2"';
$result = preg_replace($pattern, $replace, $text);

Pattern Modifiers
http://www.php.net/manual/en/referen....modifiers.php

HTH
Micha

[Aphrael]

Michael Fesser wrote:

.oO(Aphrael)

Aphrael wrote:
[snip]
And to make it more complex, if possible (but I doubt that), if somelink
== linkface, i would like to display only linkface. Possible with
ereg_replace ? or preg_replace ?

Sure. ;)
The magic needed in this case is the modifier 'e'.

$text = '<A HREF="somelink" maybesomthing="heretoo">linkface</A>';
$pattern = '#<a href="(.+)".*>(.+)</a>#eisU';
$replace = '"$1" == "$2" ? "$1" : "($1) $2"';
$result = preg_replace($pattern, $replace, $text);

Pattern Modifiers
http://www.php.net/manual/en/referen....modifiers.php

HTH
Micha

Well, well, well. I do not understand the slightest part of all that,
but... it works, so... THANK YOU :D

Aphrael...
--
"La demande mondiale d’ordinateurs n’excédera pas cinq machines."
(Thomas Watson, Fondateur d'IBM, 1945)

[Aphrael]

Christopher Finke wrote:

"Aphrael" <ap*****@isuisse.com> wrote in message
news:41********@news.bluewin.ch...

I would like a regular expression to do so:
Base:
<A HREF="somelink" maybesomthing="heretoo">linkface</A>
and I want:
(somelink) linkface
Is this possible ? If yes, how ?

Perhaps something like this:

$string = '<A HREF="somelink" maybesomthing="heretoo">linkface</A>';

$newstring = preg_replace("/<a href=\"(.*)\".*>(.*)</a>/Uis","(\\1) \\2",
$string);

Chris Finke

Thanks, too, but it returns an error (about an a pattern or something
like that...)

Aphrael...
--
"La demande mondiale d’ordinateurs n’excédera pas cinq machines."
(Thomas Watson, Fondateur d'IBM, 1945)

[Michael Fesser]

.oO(Aphrael)

Christopher Finke wrote:

$newstring = preg_replace("/<a href=\"(.*)\".*>(.*)</a>/Uis","(\\1) \\2",

^
Thanks, too, but it returns an error (about an a pattern or something
like that...)

There's an unescaped slash in the pattern. In this case it becomes a
problem because slashes are also used as pattern delimiters.

Micha

[Chung Leong]

"Aphrael" <ap*****@isuisse.com> wrote in message
news:41********@news.bluewin.ch...

And by the way, if anyone has a GOOD and CLEAR explanation about regular
expressions... please post it :-)

What you need is the camel book.

[Aphrael]

Chung Leong wrote:

"Aphrael" <ap*****@isuisse.com> wrote in message
news:41********@news.bluewin.ch...

And by the way, if anyone has a GOOD and CLEAR explanation about regular
expressions... please post it :-)

What you need is the camel book.

huuuuh... ok, thanks, will have a look *walks away puzzled...*

Aphrael...
--
"La demande mondiale d’ordinateurs n’excédera pas cinq machines."
(Thomas Watson, Fondateur d'IBM, 1945)

[Aphrael]

Michael Fesser wrote:

.oO(Aphrael)

Christopher Finke wrote:

$newstring = preg_replace("/<a href=\"(.*)\".*>(.*)</a>/Uis","(\\1) \\2",

^

Thanks, too, but it returns an error (about an a pattern or something
like that...)

There's an unescaped slash in the pattern. In this case it becomes a
problem because slashes are also used as pattern delimiters.

Micha

Ok, will try to correct that... :-)

Aphrael...
--
"La demande mondiale d’ordinateurs n’excédera pas cinq machines."
(Thomas Watson, Fondateur d'IBM, 1945)