Negate glob() pattern

[Franz Marksteiner]

Hi folks,

is there a way to negate a glob() pattern?
What I want is to get a tree structure, e.g. all .php files *and* all
directories.
How would I start here?

--
Freundliche Grüße,
Franz Marksteiner

[petersprc]

Hi,

The find command can search within a directory tree:

$dir = dirname(__FILE__);
$cmd = 'find ' . escapeshellarg($dir) . ' -name "*.php" ' .
'-o -type d 2>&1';
exec($cmd, $output, $exitCode);
if ($exitCode != 0) {
throw new Exception("Command \"$cmd\" failed with " .
"exit code $exitCode: " . join("\n", $output));
}
echo "Found " . count($output) . " entries.<br>\n";

As for glob, you can just call it multiple times: once with *.php and
once with the GLOB_ONLYDIR flag.

You could also use opendir/readdir.

On Mar 16, 5:31 pm, "Franz Marksteiner" <[e-mail]>
wrote:

Hi folks,

is there a way to negate a glob() pattern?
What I want is to get a tree structure, e.g. all .php files *and* all
directories.
How would I start here?

--
Freundliche Grüße,
Franz Marksteiner

[Franz Marksteiner]

petersprc wrote:

As for glob, you can just call it multiple times: once with *.php and
once with the GLOB_ONLYDIR flag.

Yeah, I guess that makes sense.

You could also use opendir/readdir.

The thing is that glob seems to be way easier with the pattern
functionality.
In the past I did use opendir.

What would you prefer?

On Mar 16, 5:31 pm, "Franz Marksteiner" <[e-mail]>
wrote:

>Hi folks,

is there a way to negate a glob() pattern?
What I want is to get a tree structure, e.g. all .php files *and* all
directories.
How would I start here?

--
Freundliche Grüße,
Franz Marksteiner

--
Freundliche Grüße,
Franz Marksteiner