shell_exec() function

[Akkad]

hi, i am having problem using shell_exec() function:
<code>
echo shell_exec("cat `find ./logs -name access.log*` | grep akadi_icho | ./calamaris/calamaris -a -P 60 -T 0 -r 400 -d 500 -u -O -w");
</code>
i am not getting the ouput file, though the command string passed in the function is working perfectly when used on the shell.

but when i am trying to execute it using this function in a php file, no ouput file is made.
so plz if anyone have an idea about this plz help me.

regards

[vituko]

Does your hosting allow you to access the shell? Usually does not.
I see nothing strange in this statement...

[Akkad]

Actually i have full access to the shell but running this code in a php file on xampp server that i have on the linux, i am not getting the output even when i am trying to pipe the output to an html file .
<code>

shell_exec("cat `find ./logs -name access.log*` | grep akadi_icho | ./calamaris/calamaris -a -P 60 -T 0 -r 400 -d 500 -u -O -F html>akadi_icho.html");

</code>
but when i am running this code on the shell directly :
<code>
cat `find ./logs -name access.log*` | grep akadi_icho| ./calamaris/calamaris -a -P 60 -T 0 -r 400 -d 500 -u -O -F html>akadi_icho.html
</code>
it is working perfectly.
so i have tried to run the code in parts :
<code>
shell_exec("cat `find ./logs -name access.log*` | grep akadi_icho");
</code>
this part is working, but when i am running the whole part i am not getting any output.

so plz can u help me to figure out the problem.