Error: $end on line 64

6 New Member

I've getting an error: Parse error: syntax error, unexpected $end on line 64

Can someone see were I type it wrong.

Thanks..

Expand|Select|Wrap|Line Numbers

 
<?php

    require("database.inc.php");

{connectDatabase();

?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />

<title>V&aelig;lg lyd til <?=$_POST['title']?></title>

<link href="style.css" rel="stylesheet" type="text/css" />

</head>
 
<body>

<? if(file_exists("text/".$_POST['title'].".txt")) {

?>

<h1>V&aelig;lg lyd</h1>

<h3 style="color:#CC3333">Pas p&aring;! Der findes allerede et diktat med denne titel.<br />

Hvis du er ved at lave et nyt diktat, burde du g&aring; <a href="javascript:history.back()">tilbage</a> og v&aelig;lge en anden titel.

G&oslash;r du ikke det, bliver diktatet med titelen &quot;<?=$_POST['title']?>&quot; erstattet med dette diktat her!</h3>

<?php

}

?>

<form enctype="multipart/form-data" action="save_dict.php" method="post">

<input type="hidden" name="MAX_FILE_SIZE" value="500000" />

<table border="0">

<?php

    $result=mysql_query("SELECT word FROM repository;");

    while($entry=mysql_fetch_array($result)) {

      if(! $result)

          exit(mysql_error());

    }

    $word_start=0;

    $word_stop=0;

    $open=false;

    $words=array();

    $content=$_POST['content'];

    for($i=0;$i<strlen($content);$i++) {

        if(substr($content,$i,1)=="<" && !$open) {

            $word_start=$i+1;

            $open=true;

        }

        elseif(substr($content,$i,1)==">" && $open) {

            $word_stop=$i;

            $word=substr($content,$word_start,$word_stop-$word_start);

            if(!in_array($word,$repository)) {

                $words[]=$word;

                ?>

                <tr>

                    <td><?=$word?></td>

                    <td><input type="file" name="<?=$word?>" /></td>

                </tr>

                <?

            }

            $open=false;

        }

    }

?>

</table>

<input type="hidden" name="words" value="<? echo implode(";",$words); ?>" />

<input type="hidden" name="content" value="<?=$_POST['content']?>" />

<input type="hidden" name="title" value="<?=$_POST['title']?>" />

<input type="submit" value="Upload &amp; gem" />

</form>

</body>

</html>

Jul 12 '07 #1

Subscribe Reply

1552

ilearneditonline

130

Recognized Expert New Member

I've getting an error: Parse error: syntax error, unexpected $end on line 64

Can someone see were I type it wrong.

Thanks..

Expand|Select|Wrap|Line Numbers

<?php

require("database.inc.php");

{connectDatabase();

You have an open bracket, but I never noticed a closing bracket. That would cause that error.

Jul 12 '07 #2

Goldenlamp

New Member

I've still getting the same error $end on line 66. But I think that the problem isn't in the start of the php. but maby and only maby the end of the PHP.
Something is not closed properly...

Expand|Select|Wrap|Line Numbers

 
<?php

    require("database.inc.php");

{connectDatabase();

?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />

<title>V&aelig;lg lyd til <?=$_POST['title']?></title>

<link href="style.css" rel="stylesheet" type="text/css" />

}

</head>
 
<body>

<? if(file_exists("text/".$_POST['title'].".txt")) {

?>

<h1>V&aelig;lg lyd</h1>

<h3 style="color:#CC3333">Pas p&aring;! Der findes allerede et diktat med denne titel.<br />

Hvis du er ved at lave et nyt diktat, burde du g&aring; <a href="javascript:history.back()">tilbage</a> og v&aelig;lge en anden titel.

G&oslash;r du ikke det, bliver diktatet med titelen &quot;<?=$_POST['title']?>&quot; erstattet med dette diktat her!</h3>

<?

}

?>

<form enctype="multipart/form-data" action="save_dict.php" method="post">

<input type="hidden" name="MAX_FILE_SIZE" value="500000" />

<table border="0">

<?

    $result=mysql_query("SELECT word FROM repository;");

    while($entry=mysql_fetch_array($result)) {

      if(! $result)

          exit(mysql_error());

    }

    $word_start=0;

    $word_stop=0;

    $open=false;

    $words=array();

    $content=$_POST['content'];

    for($i=0;$i<strlen($content);$i++) {

        if(substr($content,$i,1)=="<" && !$open) {

            $word_start=$i+1;

            $open=true;

        }

        elseif(substr($content,$i,1)==">" && $open) {

            $word_stop=$i;

            $word=substr($content,$word_start,$word_stop-$word_start);

            if(!in_array($word,$repository)) {

                $words[]=$word;

                ?>

                <tr>

                    <td><?=$word?></td>

                    <td><input type="file" name="<?=$word?>" /></td>

                </tr>

                <?

            }

            $open=false;

        }

    }

?>

</table>

<input type="hidden" name="words" value="<? echo implode(";",$words); ?>" />

<input type="hidden" name="content" value="<?=$_POST['content']?>" />

<input type="hidden" name="title" value="<?=$_POST['title']?>" />

<input type="submit" value="Upload &amp; gem" />

</form>

</body>

</html>

Jul 12 '07 #3

epots9

1,351

Recognized Expert Top Contributor

u still didn't fix the error, u still have a '{' on line 3 where there shouldn't be. Also the error doesn't mean its at the end...kind of....it means that when it finished parsing the document it got to the end of the document and it was looking for something (lets say a '}') since it couldn't find it its complaining, but that '}' could have gone at the top, the point is that the parser we looking for something it didn't find it and its crying.

Jul 12 '07 #4

ilearneditonline

130

Recognized Expert New Member

Notice that in both errors, it is complaining on the very last line. There is not any PHP code on the last line. Don't be fooled by line numbers with errors. If you forget to close a bracket, it doesn't report it on the line where the open bracket is located, because really the end bracket could be meant to be on the very last line. The error is simply telling you that it parsed everything to the very end and never found the closing bracket.

Jul 12 '07 #5

Purple

404

Recognized Expert Contributor

Hi

Try this:

[PHP]<?php
require("database.inc.php");
connectDatabase();
?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Vælg lyd til <?=$_POST['title']?></title>
<link href="style.css" rel="stylesheet" type="text/css" />
</head>
<body>
<?php if(file_exists("text/".$_POST['title'].".txt"))
{
echo '<h1>Vælg lyd</h1>
<h3 style="color:#CC3333">Pas på! Der findes allerede et diktat med denne titel.<br />
Hvis du er ved at lave et nyt diktat, burde du gå <a href="javascript:history.back()">tilbage</a> og vælge en anden titel.
Gør du ikke det, bliver diktatet med titelen '.$_POST['title'].' erstattet med dette diktat her!</h3>';
}
echo '<form enctype="multipart/form-data" action="save_dict.php" method="post">
<input type="hidden" name="MAX_FILE_SIZE" value="500000" />
<table border="0">';
$result=mysql_query("SELECT word FROM repository;");
while($entry=mysql_fetch_array($result))
{
if(! $result) exit(mysql_error());
}
$word_start=0;
$word_stop=0;
$open=false;
$words=array();
$content=$_POST['content'];
for($i=0;$i<strlen($content);$i++)
{
if(substr($content,$i,1)=="<" && !$open)
{
$word_start=$i+1;
$open=true;
}
elseif(substr($content,$i,1)==">" && $open)
{
$word_stop=$i;
$word=substr($content,$word_start,$word_stop-$word_start);
if(!in_array($word,$repository))
{
$words[]=$word;
echo '<tr><td><'.$word.'</td><td><input type="file" name="'.$word.'" /></td></tr>';
}
$open=false;
}
}
?>
</table>
<input type="hidden" name="words" value="<? echo implode(";",$words); ?>" />
<input type="hidden" name="content" value="<?=$_POST['content']?>" />
<input type="hidden" name="title" value="<?=$_POST['title']?>" />
<input type="submit" value="Upload & gem" />
</form>
</body>
</html>[/PHP]

Regards Purple

Jul 12 '07 #6

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