Parameters to SQL statements

[Stephen Poley]

I'm new to PHP. I have successfully set up a small script which pulls
data out of an Access database and puts it in an HTML page, using an SQL
query:
"SELECT * FROM ZWobservations WHERE Country = 'CY'"

I now want to parameterise this, like:
"SELECT * FROM ZWobservations WHERE Country = ?"

but have not managed to work out how to get this running. I'm getting
errors like:
"Warning: SQL error: [Microsoft][ODBC Microsoft
Access-stuurprogramma]Het veld COUNT is onjuist , SQL state 07001 in
SQLExecute"

The PHP manual is short on examples (to put it mildly) and Googling for
a tutorial or working example has had a surprising lack of success -
apparently I'm choosing just the wrong search terms.

Could someone point me to a working example / tutorial?

--
Stephen Poley
Barendrecht, Holland

[sotto]

Try something like:

$parm = "CY";
$sql = "SELECT * FROM ZWobservations WHERE Country = '$parm'";

also take a look at the sql statement "select * from x where y like
'%test%'"

hope this helps

On Fri, 18 Jul 2003 13:36:29 +0200, Stephen Poley wrote:

I'm new to PHP. I have successfully set up a small script which pulls data
out of an Access database and puts it in an HTML page, using an SQL query:
"SELECT * FROM ZWobservations WHERE Country = 'CY'"

I now want to parameterise this, like: "SELECT * FROM ZWobservations WHERE
Country = ?"

but have not managed to work out how to get this running. I'm getting
errors like:
"Warning: SQL error: [Microsoft][ODBC Microsoft Access-stuurprogramma]Het
veld COUNT is onjuist , SQL state 07001 in SQLExecute"

The PHP manual is short on examples (to put it mildly) and Googling for a
tutorial or working example has had a surprising lack of success -
apparently I'm choosing just the wrong search terms.

Could someone point me to a working example / tutorial?

[Stephen Poley]

On Fri, 18 Jul 2003 13:44:01 +0200, "sotto" <ju**@sotto.be> wrote:

Try something like:

$parm = "CY";
$sql = "SELECT * FROM ZWobservations WHERE Country = '$parm'";

also take a look at the sql statement "select * from x where y like
'%test%'"

hope this helps

Well, yes I can do it that way of course. But it seems to render the
odbc_prepare and odbc_execute calls rather redundant - to say nothing of
the parameters_array parameter to odbc_execute. One ends up using
odbc_exec the whole time. I've done it using SQL parameters in Perl, and
the PHP manual certainly makes it look as if the intention is to do it
similarly, but I'm missing out on the fine detail somewhere.

--
Stephen Poley
Barendrecht, Holland