REGEX! Argh!

[The Plankmeister]

I'm sure this should work:

echo preg_replace("/(\w)(\!w)(\w)/","\\1\. \\3","this is.a test.to see. if
it. works");

It should output:

this is. a test. to see. if it. works

But it doesn't. The string is unaltered. What am I doing wrong?

[Andy Hassall]

On Wed, 24 Dec 2003 00:28:02 +0100, "The Plankmeister"
<pl******************@hotmail.com> wrote:

I'm sure this should work:

echo preg_replace("/(\w)(\!w)(\w)/","\\1\. \\3","this is.a test.to see. if
it. works");

It should output:

this is. a test. to see. if it. works

But it doesn't. The string is unaltered. What am I doing wrong?

What is \!w ? Did you want \W (non-word character)?

Did you really want to replace with \. instead of .? (. is not special in the
_replacement_).

$1 is the preferred syntax over \1 for matches (particularly within regexes
when used as backreferences because of the ambiguities with character codes).

Perhaps:

echo preg_replace("/(\w)(\W)(\w)/",
"$1. $3",
"this is.a test.to see. if it. works");

--
Andy Hassall (an**@andyh.co.uk) icq(5747695) (http://www.andyh.co.uk)
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