Dereferencing variable name

[Owen Funkhouser]

Maybe someone can help me out here:

$name1 = "Owen";
$name2 = "Funkhouser";

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = $name$i -->\n";
}

I'd like to see:

<!-- name1 = Owen -->
<!-- name2 = Funkhouser -->

Instead, I get:

<!-- name1 = 1 -->
<!-- name2 = 2 -->

What am I doing wrong?

[Phlarmf]

"Owen Funkhouser" <fu**@highwaay.net> wrote in message
news:3F***************@highwaay.net...

Maybe someone can help me out here:

$name1 = "Owen";
$name2 = "Funkhouser";

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = $name$i -->\n";
}

I'd like to see:

<!-- name1 = Owen -->
<!-- name2 = Funkhouser -->

Instead, I get:

<!-- name1 = 1 -->
<!-- name2 = 2 -->

What am I doing wrong?

Dynamic variable names are done with the double dollar sign. Try this:

$name1 = "Owen";
$name2 = "Funkhouser";

for ($i = 1; $i < 3; $i++ ) {
$varName = "name{$i}";
echo "<!-- $varName = $$varName -->\n";
}

[Owen Funkhouser]

Phlarmf wrote:

"Owen Funkhouser" <fu**@highwaay.net> wrote in message
news:3F***************@highwaay.net...

Maybe someone can help me out here:

$name1 = "Owen";
$name2 = "Funkhouser";

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = $name$i -->\n";
}

I'd like to see:

<!-- name1 = Owen -->
<!-- name2 = Funkhouser -->

Instead, I get:

<!-- name1 = 1 -->
<!-- name2 = 2 -->

What am I doing wrong?

Dynamic variable names are done with the double dollar sign. Try this:

$name1 = "Owen";
$name2 = "Funkhouser";

for ($i = 1; $i < 3; $i++ ) {
$varName = "name{$i}";
echo "<!-- $varName = $$varName -->\n";
}

I really want to avoid having another variable around. But you got me going in the right
direction. The following seems to work well:

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = ${"name$i"} -->\n";
}

[Jochen Daum]

Hi Owen!

I really want to avoid having another variable around. But you got me going in the right
direction. The following seems to work well:

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = ${"name$i"} -->\n";
}

If you want to avoid unnecessary variables you might want to look into
arrays. See www.php.net

HTH,Jochen

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PHP DB Edit Toolkit -- PHP scripts for building
database editing interfaces.
http://sourceforge.net/projects/phpdbedittk/

[Owen Funkhouser]

Jochen Daum wrote:

Hi Owen!

I really want to avoid having another variable around. But you got me going in the right
direction. The following seems to work well:

for ($i = 1; $i < 3; $i++ ) {
echo "<!-- name$i = ${"name$i"} -->\n";
}

If you want to avoid unnecessary variables you might want to look into
arrays. See www.php.net

The data actually ends up in an array; I elided that information. In a nutshell, I'm
converting input from a form's POST into an array.

[Zurab Davitiani]

Owen Funkhouser wrote on Wednesday 24 September 2003 09:29:

The data actually ends up in an array; I elided that information. In a
nutshell, I'm converting input from a form's POST into an array.

If you have control over the form being submitted, use an array when
assigning form element names, such as:

<input type="text" name="arr[0]" />
<input type="text" name="arr[1]" />
etc.

After the form is submitted, the resulting variable $_POST["arr"] will be an
array also.

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ActiveLink, LLC
www.active-link.com/intranet/

[Owen Funkhouser]

Zurab Davitiani wrote:

Owen Funkhouser wrote on Wednesday 24 September 2003 09:29:

The data actually ends up in an array; I elided that information. In a
nutshell, I'm converting input from a form's POST into an array.

If you have control over the form being submitted, use an array when
assigning form element names, such as:

<input type="text" name="arr[0]" />
<input type="text" name="arr[1]" />
etc.

After the form is submitted, the resulting variable $_POST["arr"] will be an
array also.

Thank you! This will remove many large chunks of code and reduce the size of the SDD
greatly.

[Geoff Berrow]

I noticed that Message-ID:
<sk*****************@newssvr25.news.prodigy.com> from Zurab Davitiani
contained the following:

<input type="text" name="arr[0]" />
<input type="text" name="arr[1]" />
etc.

After the form is submitted, the resulting variable $_POST["arr"] will be an
array also.

So the values will be in $_POST["arr[0]"],$_POST["arr[1]"] and so on?

--
Geoff Berrow
It's only Usenet, no one dies.
My opinions, not the committee's, mine.
Simple RFDs http://www.ckdog.co.uk/rfdmaker/

[Pedro]

On Thu, 25 Sep 2003 00:09:52 +0100, Geoff Berrow wrote:

So the values will be in $_POST["arr[0]"],$_POST["arr[1]"] and so on?

Not quite, but very near :-)

The values will be in $_POST['arr'][0], $_POST['arr'][1], etc
and you can treat the array with the foreach construct:

<?php
echo '<table>';
foreach ($_POST['arr'] as $k=>$v) {
echo '<tr><td>', $k, '</td><td>', $v, '</td></tr>';
}
echo '</table>';
?>

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