PHP Program Execution Problem

[gojuka]

Hi All

Im having a minor issue performing a system command with exec(). I
want to use the filenames of files that I uploaded within the command,
but cannot escape once inside the exec() function. For example, lets
say I just uploaded two files, file1.txt and file2.txt. I want to list
the contents of those two files by using the command:

cat file1.txt file2.txt

But I'm having problems using the names of the files uploaded. I used
a for loop to grab each file name and put them in an array, and can
successfully view the array to verify its contents. The problem occurs
when I try this:

exec('cat " . $Array['0'] . " ....blah blah

This is just an example so you can understand what Im trying to
accomplish.

TIA
Rob

[Steve]

cat file1.txt file2.txt But I'm having problems using the names of the files uploaded. I used
a for loop to grab each file name and put them in an array, and can
successfully view the array to verify its contents. The problem occurs
when I try this: exec('cat " . $Array['0'] . " ....blah blah

You probably need to move the files from the temporary upload directory
before you can process them.

See <http://www.php.net/features.file-upload> and
<http://www.php.net/manual/en/function.move-uploaded-file.php>.

---
Steve