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Include Problem ?

Xav
Why does this not work ?

$fileDir = '../folder2/';
$content is an array of php files, file1.php file2.php file3.php
etc...

$c = count($content) ;
for( $x=0; $x<$c; $x++ ){
include( $fileDir.$conte nt[$x] );
}

any ideas would be appreciated,
thanks.
Xav

Oct 26 '07 #1
4 1103
Xav
this seems to work,

....
for( $x=0; $x<$c; $x++ ){
include( $fileDir.'file' .($x+1).'.php' );

}
....

I don't understand why the other won't !
???

Xav

Oct 26 '07 #2
Xav schrieb:
Why does this not work ?
$fileDir = '../folder2/';
$content is an array of php files, file1.php file2.php file3.php
etc...
$c = count($content) ;
for( $x=0; $x<$c; $x++ ){
include( $fileDir.$conte nt[$x] );
}
This should work if $content really contains what you expect.

var_dump($conte nt);
Oct 26 '07 #3
Xav
I did the <pre>...</prething...
it shows;

[0] =file1.php
[1] =file2.php
etc...

as expected!

I think I found a Bug!

this really doesn't work, I was thinking my logic was at fault,

could it be a php.ini setting problem ? I don't know of any settings
that govern logic.

thanks for response,
Xav

Oct 26 '07 #4
On Fri, 26 Oct 2007 10:47:45 +0200, Xav <xa****@inbox.c omwrote:
I did the <pre>...</prething...
it shows;

[0] =file1.php
[1] =file2.php
etc...

as expected!

I think I found a Bug!
Not very likely.
Do this:

$c = count($content) ;
for( $x=0; $x<$c; $x++ ){
echo "|{$fileDir}{$c ontent[$x]}|\n";
}

The pipes are there to discover whitespace, a normal space would account
for the difference. Normally I'd be against using <pre>, just look at the
source. And please enable error_reporting & display_errors while
developing, and tell us why PHP sais the include fails.
--
Rik Wasmus
Oct 26 '07 #5

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