hey there,
i m trying to get only time information of a date type variable.
i got a column in type of char, it keeps time info in hh:mm format - 5 characters
when i tried to convert it to date with to_date([variable], 'hh24:mi') it gives me a date starts with the ifrst day of current mount, year etc.
01/10/2008 14:04 for example.
i need a solution to get time info in date data type from a char column in hh:mm
thanx for ypur care...
6  11430 
Your requimrent is not clear.Are you trying to convert the char data in to time format or are you trying to extract a time from a current date?
i m trying to convert char data (for example 15:30) into date data type.
to_date('15:30' ,'hh24:mi') function gives it to me with a date that belong to first day of the current mount. for example as 01/10/2008 15:30 i f we cosider today. i need only time info.
thanks for your care...
Gözde
You can store both date a dnd time in a date value .Which can later be extracted as desired for any processing or rerporting purpose.
i m trying to convert char data (for example 15:30) into date data type.
to_date('15:30' ,'hh24:mi') function gives it to me with a date that belong to first day of the current mount. for example as 01/10/2008 15:30 i f we cosider today. i need only time info.
thanks for your care...
Gözde
Use TO_CHAR(column_ name,'HH24:MI') or TO_CHAR(TO_DATE ('15:30','HH24: MI'),'HH24:MI')
Use TO_CHAR(column_ name,'HH24:MI') or TO_CHAR(TO_DATE ('15:30','HH24: MI'),'HH24:MI')
sorry that i think i couldn't explain my problem clearly
above fınctions gives it to me as character. i need time info in date type. when i use to_date() with 'hh24:mi' it gives me with an unwanted date info. i need only time...
try to use EXTRACT function.
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