Add LDAP member to LDAP group!

[Ilios78]

Hi folks,
I have been trying (in C# 2.0) using several ways to add an LDAP Member object to a group.

Below you can see the code and two of the ways I tried:

DirectoryEntry newEntry; 
 
 //.....
 // Creating the LDAP member entry.....no problems here!!!
 //....
 
using (DirectoryEntry groupEntry = GetGroupEntry())
{                
        groupEntry.Properties["member"].Add(newEntry.Path);
        groupEntry.CommitChanges();   <-- Exception here
}
 
COMException: ex = {"The attribute type specified to the directory service is not defined. (Exception from HRESULT: 0x8007200C)"}

I have also tried:
groupEntry.Invoke("Add", new object[] { newEntry.Path });
In this case I get:
"Unknown name. (Exception from HRESULT: 0x80020006 (DISP_E_UNKNOWNNAME))"
right after the Invoke method!

Any help or comment is most appricated!

[kenobewan]

Seems to be a problem with newEntry.Path. What is its value?

[Ilios78]

Seems to be a problem with newEntry.Path. What is its value?

The newEntry object is created and used with no problems!
newEntry.Path = "LDAP://dev1:1003/cn=myuser1,ou=Members,o=InMembership"

[kenobewan]

So you are trying to add the ldap query as a property of the group entry member?

[Ilios78]

So you are trying to add the ldap query as a property of the group entry member?

Ok.. Is that wrong? What should I pass to the "add" method. Besides from the exception I get I think the group entry does not have a "member" property. Not that it does not understand the user entry object! But please let me know if you still think I am doing something wrong!

Thanks

[kenobewan]

I thought that you would have wanted to add group properties such name. I don't believe the ldap query is a valid property of the group. HTH.

[Ilios78]

I thought that you would have wanted to add group properties such name. I don't believe the ldap query is a valid property of the group. HTH.

The Path property is what uniquely defines an LDAP entry! I did try (just for being sure) passing the username and “name” property but as expected I got the same COM exception.