Get attribute from Xml file

[Steve]

I'm looking to get noNamespaceSchemaLocation attribute from the
following Xml file. Whats the most efficient way to do this using the
XmlDocument class in c#?
<?xml version="1.0"?>
<IPDRDoc xmlns="http://www.ipdr.org/namespaces/ipdr"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="email.xsd"
docId="d0af6d45-00f8-5000-f930-01760a250156"
creationTime="2003-11-12T16:04:07.046Z"
IPDRRecorderInfo="IPDRDocTest"
version="3.1">
<IPDR xsi:type="IPDR-EMAIL-Type" >
<IPDRCreationTime>2003-11-12T16:04:07.281Z</IPDRCreationTime>
<seqNum>1</seqNum>
<serviceProviderID>TSSG12</serviceProviderID>
<subscriberId>Sean Hearne</subscriberId>
<userLoginName>shearne1978</userLoginName>
<userLoginLocation>192.156.12.14</userLoginLocation>
<providerName>TSSG</providerName>
<providerLocation>208.99.88.99</providerLocation>
<eventType>Storage</eventType>
</IPDR>
<IPDRDoc.End
count="1"
endTime="2003-11-12T16:04:07.281Z">
</IPDRDoc.End>
</IPDRDoc>

[Oleg Tkachenko]

Steve wrote:

I'm looking to get noNamespaceSchemaLocation attribute from the
following Xml file. Whats the most efficient way to do this using the
XmlDocument class in c#?
<?xml version="1.0"?>
<IPDRDoc xmlns="http://www.ipdr.org/namespaces/ipdr"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="email.xsd"

doc.DocumentElement.GetAttribute("noNamespaceSchem aLocation",
"http://www.w3.org/2001/XMLSchema-instance")

--
Oleg Tkachenko
XML Insider
http://www.tkachenko.com/blog