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How to say it in XSD? (xs:list, xs:enumeration, ...)

Max
Suppose I have a simple type which is enumeration

<xs:simpleType name="fontStyle">
<xs:restriction base="xs:string">
<xs:enumeration value="bold" />
<xs:enumeration value="italic" />
<xs:enumeration value="underlined" />
<xs:enumeration value="strikeout" />
</xs:restriction>
</xs:simpleType>

I want a type which is any combination of the above, so I write
<xs:simpleType name="fontStyleLst">
<xs:list itemType="fontStyle"/>
</xs:simpleType>

But, this will also allow combinations like "bold italic bold". Which has no
sense.
I would like each possible value to be allowed only once in the list.
Is their a way to write down this restriction in XSD?
Nov 12 '05 #1
1 4792
No, not for simple types like this. There is a way for complex types using
xsd:all, but that cannot be used for attribute values.

"Max" <Pl****@reply.to.news.group> wrote in message
news:eV**************@TK2MSFTNGP10.phx.gbl...
Suppose I have a simple type which is enumeration

<xs:simpleType name="fontStyle">
<xs:restriction base="xs:string">
<xs:enumeration value="bold" />
<xs:enumeration value="italic" />
<xs:enumeration value="underlined" />
<xs:enumeration value="strikeout" />
</xs:restriction>
</xs:simpleType>

I want a type which is any combination of the above, so I write
<xs:simpleType name="fontStyleLst">
<xs:list itemType="fontStyle"/>
</xs:simpleType>

But, this will also allow combinations like "bold italic bold". Which has no sense.
I would like each possible value to be allowed only once in the list.
Is their a way to write down this restriction in XSD?

Nov 12 '05 #2

This thread has been closed and replies have been disabled. Please start a new discussion.

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