Hello,
I'm having problems with an XSLT template I'm developing.
I have a date in an odd format which I'm trying to convert into something
more readable. The original date is in the format YYYY-MM-DD, and I'd like
to convert it to DD MON YY.
I pass the date into my template thusly in my XSLT stylesheet (date-updated
is the data I'm passing in):
<xsl:call-template name="formatDat e">
<xsl:with-param name="string" select="date-updated" />
</xsl:call-template>
.... and the template is thus:
<xsl:template name="formatDat e">
<xsl:param name="inDate" />
<!-- Day -->
<xsl:variable name="day" select="number( substring($inDa te, 9, 2))" />
<!-- Month -->
<xsl:variable name="month" select="number( substring($inDa te, 6, 2))" />
<xsl:variable name="converted-month">
<xsl:choose>
<xsl:when test="$month=fo rmat-number('01', '00')">
<xsl:value-of select="Jan" />
</xsl:when>
....
<xsl:when test="$month='1 2'">
<xsl:value-of select="Dec" />
</xsl:when>
</xsl:choose>
</xsl:variable>
<!-- Year -->
<xsl:variable name="year" select="number( substring($inDa te, 3, 2))" />
<!-- Formatted Date -->
<xsl:value-of select="concat( $inDate, ': ', format-number($day, '00'), '
', $converted-month, ' ', format-number($year, '00'))" />
</xsl:template>
The output I get is:
: NaN NaN
NaN = Not a number, of course, but I can't see why such an error should be
raised.
Thanks for any assistance,
Mark 6 2859
Mark wrote: <xsl:call-template name="formatDat e"> <xsl:with-param name="string" select="date-updated" /> </xsl:call-template>
... and the template is thus:
<xsl:template name="formatDat e"> <xsl:param name="inDate" />
I think you need
<xsl:param name="string" />
here or
<xsl:with-param name="inDate" select="date-updated" />
above, the name of the parameter needs to be the same in xsl:with-param
and xsl:param.
--
Martin Honnen http://JavaScript.FAQTs.com/
> I think you need <xsl:param name="string" /> here or <xsl:with-param name="inDate" select="date-updated" /> above, the name of the parameter needs to be the same in xsl:with-param and xsl:param.
Yes, you're right - thanks.
Mark
> Yes, you're right - thanks.
Another problem - the month comes in as a 2 digit number (e.g. 01 for Jan).
How can I convert it to the text "Jan"?
I've tried the following:
<xsl:variable name="month" select="number( substring($inDa te, 6, 2))"/>
<xsl:variable name="converted-month">
<xsl:choose>
<xsl:when test="$month='1 '">
<xsl:value-of select="Jan"/>
</xsl:when>
....
</xsl:choose>
</xsl:variable>
.... but the match is never made: it always produces no output.
I've tried outputting $month, and that produces the correct month number
(e.g. "1", rather than "01"), so the correct data is going in. I just can't
seem to get the comparison right.
Thanks for any information,
Mark
In article <40************ ***********@new s.easynet.co.uk >, Mark wrote: Another problem - the month comes in as a 2 digit number (e.g. 01 for Jan).
How can I convert it to the text "Jan"?
I've tried the following:
<xsl:variable name="month" select="number( substring($inDa te, 6, 2))"/> <xsl:variable name="converted-month"> <xsl:choose> <xsl:when test="$month='1 '"> <xsl:value-of select="Jan"/> </xsl:when> ... </xsl:choose> </xsl:variable>
... but the match is never made: it always produces no output.
The match is made, but <xsl:value-of select="Jan"/> is the value of the
element named "Jan". Because there is no element named "Jan", the value
is empty. If you want the value to be a string use
<xsl:value-of select="'Jan'"/>
If you want the value to be a text node use
<xsl:text>Jan </xsl:text>
> The match is made, but <xsl:value-of select="Jan"/> is the value of the element named "Jan". Because there is no element named "Jan", the value is empty. If you want the value to be a string use
<xsl:value-of select="'Jan'"/>
If you want the value to be a text node use
<xsl:text>Jan </xsl:text>
Great - thank you very much.
Mark
Mark <ma************ ****@ukonline.c o.uk.nospam> wrote: I have a date in an odd format which I'm trying to convert into something more readable. The original date is in the format YYYY-MM-DD, and I'd like to convert it to DD MON YY.
As an aside, what's so "odd" about the ISO (8601) date format? http://www.hermetic.ch/cal_stud/formats.htm
--
_Deirdre web: http://deirdre.net blog: http://deirdre.org/blog/
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