How to convert a Byte array to a char array?

[Kueishiong Tu]

How do I convert a Byte array (unsigned char managed) to a
char array(unmanaged ) with wide character taken into
account?

[Nishant S]

System::Char can store both unicode as well as single byte characters.

--
Regards,
Nish [VC++ MVP]

"Kueishiong Tu" <ks****@seed.ne t.tw> wrote in message
news:3c******** *************** *****@phx.gbl.. .

-----Original Message-----
There was en error in my prev post.

char is 8 bits (a byte) and Char is 16 bits (2 bytes)

Does the 2-byte Char have a fixed length or it can adjust
to the data depending on what are stored (may be one-byte
or two-byte)?
By the way, do you know a convert routine that can
convert a Byte array to a Big-5 char array (a mixture of
one-byte and two-byte characers)?

regards,
Kueishiong Tu

[Kueishiong Tu]

-----Original Message-----
Hmmm

Okay I think one of the following is what you want :-

//this is to obtain a single byte char array
//might lose chinese characters

char smallarray[512];
for(int i=0; i<barray->Length; i++)
smallarray[i] = barray[i];

//this gets a wide char array
String* tmp = new String(Encoding ::ASCII->GetChars (barray));__wchar_t* array = (__wchar_t*) Marshal::String ToHGlobalUni( tmp).ToPointer( );
//...
// You can now use array (wide char array)
//...
Marshal::FreeC oTaskMem(array) ;

I think the second one is what you want. Please try it out and see if itworks for you.

--
Regards,
Nish [VC++ MVP]

The problem I have is that the decoding routine (already
available) expects the input to be a char array instead
of a wide char array. How do I get around this?
Does VC++ .net has the concept of locality so that you
have to set up the locality properly before it will
recognize the local language (something like sun solaris)?
I think this is done implicitly in Microsoft products.

Kueishiong Tu

[Kueishiong Tu]

I have found the solution to my problem. And the solution
is surprising easy. It is

Byte a[100];
char b[100];

for(int i=0; i<a->Length; i++)
{
b[i] = (char) a[i];
}

The resulting char array then works fine for both 1-byte
character and 2-byte character.

[Nishant S]

Considering that a Byte array *cannot* contain 2-byte characters, the last
sentence about how it's fine for both 1-byte and 2-byte characters is a moot
point

--
Regards,
Nish [VC++ MVP]

"Kueishiong Tu" <ks****@seed.ne t.tw> wrote in message
news:18******** *************** *****@phx.gbl.. .

I have found the solution to my problem. And the solution
is surprising easy. It is

Byte a[100];
char b[100];

for(int i=0; i<a->Length; i++)
{
b[i] = (char) a[i];
}

The resulting char array then works fine for both 1-byte
character and 2-byte character.

[Nishant S]

Considering that a Byte array *cannot* contain 2-byte characters, the last
sentence about how it's fine for both 1-byte and 2-byte characters is a moot
point

--
Regards,
Nish [VC++ MVP]

"Kueishiong Tu" <ks****@seed.ne t.tw> wrote in message
news:18******** *************** *****@phx.gbl.. .

I have found the solution to my problem. And the solution
is surprising easy. It is

Byte a[100];
char b[100];

for(int i=0; i<a->Length; i++)
{
b[i] = (char) a[i];
}

The resulting char array then works fine for both 1-byte
character and 2-byte character.

[Jeffrey Klug]

memcpy is probably faster.

"Nishant S" <ni**@nospam.as ianetindia.com> wrote in message
news:uM******** *****@TK2MSFTNG P12.phx.gbl...

Considering that a Byte array *cannot* contain 2-byte characters, the last
sentence about how it's fine for both 1-byte and 2-byte characters is a moot point

--
Regards,
Nish [VC++ MVP]

"Kueishiong Tu" <ks****@seed.ne t.tw> wrote in message
news:18******** *************** *****@phx.gbl.. .

I have found the solution to my problem. And the solution
is surprising easy. It is

Byte a[100];
char b[100];

for(int i=0; i<a->Length; i++)
{
b[i] = (char) a[i];
}

The resulting char array then works fine for both 1-byte
character and 2-byte character.