Transforming XML to HTML using XSL in .NET

[Sergio Otoya]

Hi all,

I need to transform an xml document, using xsl to a HTML output.

I can do this successfully using the XslTransform class as below:

Dim oTrans As New XslTransform

oTrans.Load(sXS LPath)
oTrans.Transfor m(sXMLPath, "c:\trans.h tm")

However, I need to transform everything from supplied strings. ie the
XML and XSL are provided as inputs (not the paths).

Any suggestions are appreciated. Thanks in advance.

Sergio

[Chris J.T. Auld [MVP]]

> I need to transform an xml document, using xsl to a HTML output.

However, I need to transform everything from supplied strings. ie the
XML and XSL are provided as inputs (not the paths). Any suggestions are appreciated. Thanks in advance.

See the code below...... I have avoided doing it with streams, which would
probably be a bit more efficient as using XmlDocument is a bit overkill
here, but this way should be more familiar to you given your past
experience.

Cheers
Chris

-------------------------------------------
Kognition Consulting Limited - Thought Meets Technology
Chris J.T. Auld - Managing Director
Microsoft MVP (Windows Mobile Devices)
Phone: [phone]
Mobile: [phone]
Email: ch***@spam.me.n ot.kognition.co .nz
using System;
using System.IO;
using System.Xml;
using System.Xml.XPat h;
using System.Xml.Xsl;

public class Foo
{
private const String sourceXml= @"<foo>bar</foo>";
private const String sourceXsl= @"<xsl:styleshe et version='1.0'
xmlns:xsl='http ://www.w3.org/1999/XSL/Transform'><xsl :template
match='/'>Your <xsl:value-of select='foo'/>
Here</xsl:template></xsl:stylesheet> ";

public static void Main()
{

XmlDocument xslDoc = new XmlDocument();
xslDoc.LoadXml( sourceXsl);
XslTransform xslt = new XslTransform();
xslt.Load(xslDo c.CreateNavigat or());

XmlDocument contentDoc = new XmlDocument();
contentDoc.Load Xml(sourceXml);
XmlTextWriter writer = new XmlTextWriter(C onsole.Out);
writer.Formatti ng=Formatting.I ndented;

xslt.Transform( contentDoc, null, writer, null);
}
}

[Oleg Tkachenko [MVP]]

Chris J.T. Auld [MVP] wrote:

XmlDocument xslDoc = new XmlDocument();
xslDoc.LoadXml( sourceXsl);
XslTransform xslt = new XslTransform();
xslt.Load(xslDo c.CreateNavigat or());

XmlDocument contentDoc = new XmlDocument();
contentDoc.Load Xml(sourceXml);
XmlTextWriter writer = new XmlTextWriter(C onsole.Out);
writer.Formatti ng=Formatting.I ndented;

xslt.Transform( contentDoc, null, writer, null);

Small nitpicking, sorry:
1. XPathDocument is 30% faster for XSLT than XmlDocument.
2. Transforming to XmlWriter in fact means transforming to XML, not HTML
(the whole xsl:output element is ignored).

Here is my version:

XslTransform xslt = new XslTransform();
xslt.Load(new XmlTextReader(n ew StringReader(so urceXsl)))

XPathDocument doc = new XPathDocument(n ew StringReader(so urceXml));
xslt.Transform( contentDoc, null, Console.Out, null);

--
Oleg Tkachenko [XML MVP, XmlInsider]
http://blog.tkachenko.com

[Sergio Otoya]

Brilliant! Thanks to both Oleg and Chris. The solutions worked. That
saved me heaps of time.

Sergio
"Oleg Tkachenko [MVP]" <oleg@NO!SPAM!P LEASEtkachenko. com> wrote in message news:<O0******* *******@TK2MSFT NGP12.phx.gbl>. ..

Chris J.T. Auld [MVP] wrote:

XmlDocument xslDoc = new XmlDocument();
xslDoc.LoadXml( sourceXsl);
XslTransform xslt = new XslTransform();
xslt.Load(xslDo c.CreateNavigat or());

XmlDocument contentDoc = new XmlDocument();
contentDoc.Load Xml(sourceXml);
XmlTextWriter writer = new XmlTextWriter(C onsole.Out);
writer.Formatti ng=Formatting.I ndented;

xslt.Transform( contentDoc, null, writer, null);

Small nitpicking, sorry:
1. XPathDocument is 30% faster for XSLT than XmlDocument.
2. Transforming to XmlWriter in fact means transforming to XML, not HTML
(the whole xsl:output element is ignored).

Here is my version:

XslTransform xslt = new XslTransform();
xslt.Load(new XmlTextReader(n ew StringReader(so urceXsl)))

XPathDocument doc = new XPathDocument(n ew StringReader(so urceXml));
xslt.Transform( contentDoc, null, Console.Out, null);