I have an interesting problem. I am performing an XSL
transform using the System.Xml.Xsl. Transform class.
I have a database that contains the XSL style sheet
string. And it seems to work pretty well for simple
transforms. But as soon as I add Xsl variables or For each
loops to the XSL string in the db, it fails to transform
the XML. I can see that it will transform everything until
that point. ALso If I copy the XSL & XML I am trying to
transform from my watch window into a file.. It works
perfectly. Any Ideas?
The following is the C# code I am using to transform & the
XSL I am using to transform.
//Code
XmlDocument transform = new XmlDocument();
transform.LoadX ml(DataFormat); //DataFormat xsl string
XmlUrlResolver resolver = new XmlUrlResolver( );
XslTransform xslTran = new XslTransform();
xslTran.Load(tr ansform,resolve r,null);
XmlReader reader =
xslTran.Transfo rm(XmlData,null ,resolver);
reader.MoveToCo ntent();
string readerOutput = reader.ReadOute rXml();
//XSL
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:template match="DataSour ce">
<B>Report</B><BR/>
<TABLE CELLPADDING="1" CELLSPACING="1" Border="1">
<TR><TH>Agreeme nt Number</TH>
<TH>Name</TH>
<TH>Period</TH>
<TH>Due Date</TH>
<TH>Type</TH>
</TR>
<xsl:for-each select="tblRepo rt[code='XYZ']">
<TR>
<TD><xsl:valu e-of select="Agreeme ntNumber"/></TD>
<TD><xsl:valu e-of select="Name"/></TD>
<TD><xsl:valu e-of select="Period"/></TD>
<TD><xsl:valu e-of select="DueDate "/></TD>
<TD><xsl:valu e-of select="Type"/></TD>
</TR>
</xsl:for-each>
<</xsl:template>
</xsl:stylesheet> 4 3000
John Lehmann wrote: I have an interesting problem. I am performing an XSL transform using the System.Xml.Xsl. Transform class. I have a database that contains the XSL style sheet string. And it seems to work pretty well for simple transforms. But as soon as I add Xsl variables or For each loops to the XSL string in the db, it fails to transform the XML. I can see that it will transform everything until that point. ALso If I copy the XSL & XML I am trying to transform from my watch window into a file.. It works perfectly. Any Ideas?
That's bizarre. Most likely input XML is different that you think it is
so xsl:for-each just selects nothing. You didn't show us what XmlData is.
Also it's too expensive to build XmlDocument only to feed XslTransform -
you can rewrite transformation logic in more effective way:
XmlUrlResolver resolver = new XmlUrlResolver( );
XslTransform xslTran = new XslTransform();
XmlReader r = new XmlTextReader(n ew StringReader(Da taFormat));
xslTran.Load(r, resolver,null);
StringWriter sw = new StringWriter();
xslTran.Transfo rm(XmlData,null ,sw,resolver);
string output = sw.ToString();
--
Oleg Tkachenko http://www.tkachenko.com/blog
Multiconn Technologies, Israel
John Lehmann wrote: The Xml Looks something like this: <?xml version="1.0" encoding="UTF-8"?> <DataSource> <tblReport> <AgreementNumbe r>1234567</AgreementNumber > <Name>Martha Stuart</Name> <Period>July 2000</Period> <DueDate>Augu st 15, 2000</DueDate> <Type>Type II</Type> </tblReport> </DataSource>
Well, considering that XML xsl:for-each in your stylesheet really selects nothing:
<xsl:for-each select="tblRepo rt[code='XYZ']">
because in your XML tblReport has no child Code element.
--
Oleg Tkachenko
http://www.tkachenko.c om/blog
Multiconn Technologies, Israel
Just changing the way to open the transform WORK! Thanx
for you input!
John -----Original Message----- John Lehmann wrote:
I have an interesting problem. I am performing an XSL transform using the System.Xml.Xsl. Transform class. I have a database that contains the XSL style sheet string. And it seems to work pretty well for simple transforms. But as soon as I add Xsl variables or For
each loops to the XSL string in the db, it fails to
transform the XML. I can see that it will transform everything
until that point. ALso If I copy the XSL & XML I am trying to transform from my watch window into a file.. It works perfectly. Any Ideas?That's bizarre. Most likely input XML is different that
you think it isso xsl:for-each just selects nothing. You didn't show us
what XmlData is.Also it's too expensive to build XmlDocument only to feed
XslTransform - you can rewrite transformation logic in more effective
way: XmlUrlResolv er resolver = new XmlUrlResolver( ); XslTransform xslTran = new XslTransform(); XmlReader r = new XmlTextReader(n ew StringReader
(DataFormat));xslTran.Load(r ,resolver,null) ;
StringWriter sw = new StringWriter(); xslTran.Transf orm(XmlData,nul l,sw,resolver); string output = sw.ToString();
-- Oleg Tkachenko http://www.tkachenko.com/blog Multiconn Technologies, Israel
.
Just changing the way to open the transform worked.
Unfortunately since I work on sensitive data at MS, I
could not copy everything as I see it exactly (I had to
cut out a lot of things). I may have missed my select..
But like I said.. it works now. -----Original Message----- John Lehmann wrote:
The Xml Looks something like this: <?xml version="1.0" encoding="UTF-8"?> <DataSource> <tblReport> <AgreementNumbe r>1234567</AgreementNumber > <Name>Martha Stuart</Name> <Period>July 2000</Period> <DueDate>Augu st 15, 2000</DueDate> <Type>Type II</Type> </tblReport> </DataSource> Well, considering that XML xsl:for-each in your
stylesheet really selects nothing:<xsl:for-each select="tblRepo rt[code='XYZ']">
because in your XML tblReport has no child Code element. -- Oleg Tkachenko http://www.tkachenko.c om/blog Multiconn Technologies, Israel
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