Access Crystal reports from C#.NET

[Dilini Ginige]

Hi,

I need to open a crystal report through the crystalreportfo rm viewer
in a C# project.

I used a view in the crystal report.But even when I give the logoninfo
from the code the dialog box to login to the database promts from the
application.

The coding I used is as follows.

public TableLogOnInfos AddLogOnInfo(Ta bleLogOnInfos
tableLogOnInfos ,string strViewName)
{
TableLogOnInfo logOnInfo = new TableLogOnInfo ();

// Set the connection information for the table in the report.
logOnInfo.Conne ctionInfo.Serve rName = sqlServer;
logOnInfo.Conne ctionInfo.Datab aseName = sqlDataBase;
logOnInfo.Conne ctionInfo.UserI D = sqlUserID;
logOnInfo.Conne ctionInfo.Passw ord = sqlPassword;
logOnInfo.Table Name = strViewName;

// Add the logoninfo to the logOnInfos collection.
tableLogOnInfos .Add (logOnInfo);
return tableLogOnInfos ;
}
If anybody knows whats wrong with this .Can u pls let me know.

Is it because I have assumed the view to be same as a table.??

Thx
Dilini

[Chad Z. Hower aka Kudzu]

sa******@flashm ail.com (Dilini Ginige) wrote in
news:17******** *************** **@posting.goog le.com:

Hi,

I need to open a crystal report through the crystalreportfo rm viewer
in a C# project.

I used a view in the crystal report.But even when I give the logoninfo
from the code the dialog box to login to the database promts from the
application.

The coding I used is as follows.

public TableLogOnInfos AddLogOnInfo(Ta bleLogOnInfos
tableLogOnInfos ,string strViewName)
{
TableLogOnInfo logOnInfo = new TableLogOnInfo ();

// Set the connection information for the table in the
report. logOnInfo.Conne ctionInfo.Serve rName = sqlServer;
logOnInfo.Conne ctionInfo.Datab aseName = sqlDataBase;
logOnInfo.Conne ctionInfo.UserI D = sqlUserID;
logOnInfo.Conne ctionInfo.Passw ord = sqlPassword;
logOnInfo.Table Name = strViewName;

// Add the logoninfo to the logOnInfos collection.
tableLogOnInfos .Add (logOnInfo);
return tableLogOnInfos ;
}
If anybody knows whats wrong with this .Can u pls let me know.

Is it because I have assumed the view to be same as a table.??

Thx
Dilini

--
Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/
"Programmin g is an art form that fights back"
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