I've been working on my iPhone to develop an artificial intelligence algorithm that has a syntax error on line 49:

#Sentience

Q = set()

N = []

y = []

n = []

v = []

i = []

X = 0

for N in range(len(N)):

N.append(Q)

y.append(Q)

n.append(Q)

v.append(Q)

i.append(Q)

Q = set(Q)

if len(N) == float('inf'):

break

t = 0

u = []

for u in range(len(u)):

t = t + 1

u.append(t)

if len(u) == float('inf'):

break

z = any(u)

y.insert(z, n)

v.insert(z, i)

def J ():

for n in N:

(y[n]) == y[n] in set(None, set())

T = set(J())

x = N[float('inf')] is set(v in T == all(i) in N(v[i] >= v[next(i)]))

def p ():

X = X + 1

any(x) in X(p(x) is 0) or all(x) in X(p(x) is 1)

if X > 2:

break

output = ""

while True:

l = 11

while l < 126:

l = l + 1

z = chr(l)

p ()

v = p ()

if v == 1:

o = o + z

elif v == 0:

o = o

if o == o + "":

break

print (o)

To what is this error referring:

File "compiler.py", line 49

elif v == 0:

^

SyntaxError: invalid syntax

Have a good one,

-Oliver