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This function passes 2 arguments, i.e., 'str' which is the selected list box value and 'passed_url' which is a passed url for running a php script (which contains some url query parameters, e.g. 'somescript.php?var1=value1&var2=value2&var3=value3').
The capture_value() function actually sends a Ajax request with the GET method and a URL which is formed by appending the captured list box value to the 'passed_url' url value (i.e. the 'passed_url' is changed to 'somescript.php?var1=value1&var2=value2&var3=value 3&str=value4'.
Now, what I want to do is to capture the whole generated page from running the final 'passed_url' in the same window (as if I entered 'somescript.php?var1=value1&var2=value2&var3=value3 &str=value4' in the location
field of the browser and pressed <Enter>).
In other words, I want to output in the same window the generated page from running the 'somescript.php?var1=value1&var2=value2&var3=value3 &str=value4' url address.
Below is the code listing of the Javascript file I use.
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- var xmlhttp;
- function capture_value(passed_url,str)
- {
- xmlhttp=GetXmlHttpObject();
- if (xmlhttp==null)
- {
- alert ("Browser does not support HTTP Request ");
- return;
- }
- //var url="http://www.test.local/ach_handcrfts/product.php";
- passed_url=passed_url+"&drawing_style="+str;
- passed_url=passed_url+"&sid="+Math.random();
- //alert ("url: " + url);
- xmlhttp.onreadystatechange=stateChanged;
- xmlhttp.open("GET",passed_url,true);
- xmlhttp.send(null);
- }
- function stateChanged()
- {
- if (xmlhttp.readyState == 4) {
- if (xmlhttp.status == 200) {
- window.open(xmlhttp.responseXML,"_self");
- } else {
- alert("Response Error:n" + xmlhttp.statusText);
- }
- }
- }
- function GetXmlHttpObject()
- {
- if (window.XMLHttpRequest)
- {
- // code for IE7+, Firefox, Chrome, Opera, Safari
- return new XMLHttpRequest();
- }
- if (window.ActiveXObject)
- {
- // code for IE6, IE5
- return new ActiveXObject("Microsoft.XMLHTTP");
- }
- return null;
- }
with Firebug, I can see that I have no errors, and
I get the expected GET response in the Firebug console, and when I click on it's console link with the right
button and then click on "Open in New Tab", a new browser window opens with the expected page, but this page is not generated by selecting a value in the list box, i.e. somewhere in the end of the code I need to add some code to output the whole page in the same window.
I am sure it's something simple missing or needing modification.
Could you please somebody help?
