If Statement to open a form

[AR123]

Hi
I am trying to write an if statement that will open one of 3 forms.

This dosne t seem to work. Can someone have a look over my code and let me know what you think?

if (sType == "Urgent" )
{
ABC_JSopenUrl( 'xxxx/sendmailurgent.htm?' + sGUIParameters, 400, 600, 'scrollbars=yes, resizable=yes' );
}
else
{
ABC_JSopenUrl( 'xxxxxx/sendmail.htm?' + sGUIParameters, 400, 600, 'scrollbars=yes, resizable=yes' );
}
}
if (sType == "Standard_Case" )

{
ABC_JSopenUrl( 'xxxxxx sendmailstandard.htm?' + sGUIParameters, 400, 600, 'scrollbars=yes, resizable=yes' );
}

[shane3341436]

Can u describe the problem more precisely? Looking at the code it can be seen that there is an extra paranthesis after else statement.

[AR123]

This is set up so that 3 buttons appear on my page. Urgent, Callback and Standard. It works with the urgent and callback and have only just added the standard but cant get the standard one to pop up with the correct form it pops up with the callback form. Any ideas?

[shane3341436]

else if(sType == "Standard_Case" )
{
ABC_JSopenUrl( 'xxxxxx sendmailstandard.htm?' + sGUIParameters, 400, 600, 'scrollbars=yes, resizable=yes' );
}
else
{
ABC_JSopenUrl( 'xxxxxx/sendmail.htm?' + sGUIParameters, 400, 600, 'scrollbars=yes, resizable=yes' );
}
 

I think this will work

[AR123]

Yeh that works. Thanks. Appreciate the help.