Remove characters from string

Jon

Hello all,

Would anyone please be able to help?

I would like to remove all characters after and including the @ from a
string, for example the string jo********@someplace.com would become
Joe Bloggs.

Thanks You all,

Jon

Jul 23 '05 #1

Subscribe Reply

91914

Martin Honnen

Jon wrote:

I would like to remove all characters after and including the @ from a
string, for example the string jo********@someplace.com would become
Joe Bloggs.

"jo********@someplace.com".replace(/@.*/, '')

--

Martin Honnen
http://JavaScript.FAQTs.com/

Jul 23 '05 #2

Dietmar Meier

Jon wrote:

I would like to remove all characters after and including the @ from a
string,
myString = myString.replace(/@.*/, "");

Or, compatible with very old script engines

var atpos = myString.indexOf("@");
if (atpos > -1) {
myString = myString.substring(0, atpos);
}
for example the string jo********@someplace.com would become
Joe Bloggs.

Did you mean "joe.Bloggs"?

ciao, dhgm

Jul 23 '05 #3

Mick White

Jon wrote:

Hello all,

Would anyone please be able to help?

I would like to remove all characters after and including the @ from a
string, for example the string jo********@someplace.com would become
Joe Bloggs.

Jul 23 '05 #4

RobB

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"
"http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
</head>
<body>
<script type="text/javascript">

function user(addr)
{
return addr
.replace(/^(.+)@.*$/, '$1')
.replace(/\./g, ' ')
.replace(/\b./g, function(a){return a.toUpperCase();})
}

document.write(

'<pre>' ,
user('j*******@someplace.com') ,
'\n' ,
user('b************@mydomain.au') ,
'\n' ,
user('foo.Bar@haha/vavoom.net') ,
'</pre>'

);

</script>
</body>
</html>

Jul 23 '05 #5

Dr John Stockton

JRS: In article <bb**************************@posting.google.com >,
dated Wed, 27 Apr 2005 08:44:16, seen in news:comp.lang.javascript, Jon
<Jo*******@gmail.com> posted :

I would like to remove all characters after and including the @ from a
string, for example the string jo********@someplace.com would become
Joe Bloggs.

S = "jo********@someplace.com"
S = S.split('@')[0]

is another way.

S = "jo********@someplace.com"
T = S.split('@') // T[0] & T[1] may be useful

--
© John Stockton, Surrey, UK. ?@merlyn.demon.co.uk Turnpike v4.00 IE 4 ©
<URL:http://www.jibbering.com/faq/> JL/RC: FAQ of news:comp.lang.javascript
<URL:http://www.merlyn.demon.co.uk/js-index.htm> jscr maths, dates, sources.
<URL:http://www.merlyn.demon.co.uk/> TP/BP/Delphi/jscr/&c, FAQ items, links.

Jul 23 '05 #6

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