pretty simple regex replace help needed

[tgh003]

I need to replace a number in a string

str = "http://www.example.com?test=1&cat=0&ref=123213123213";

I want to replace the 0 after the cat= part with a new number. 0 could
be any number though so i need to use a reg exp to replace it.

str = str.replace(??????,newnumber);

I need help with the ?????? part :>

Any help is greatly appreciated.

Thx!

[moi]

function reDemo() {
var r = new RegExp(/=0/)
var lnk = "http://www.example.com?test=1&cat=0&ref=123213123213";
var newlnk = lnk.replace( r, "=123" );
alert( newlnk );
}

<tg****@gmail.com> schreef in bericht
news:11**********************@f14g2000cwb.googlegr oups.com...

I need to replace a number in a string

str = "http://www.example.com?test=1&cat=0&ref=123213123213";

I want to replace the 0 after the cat= part with a new number. 0 could
be any number though so i need to use a reg exp to replace it.

str = str.replace(??????,newnumber);

I need help with the ?????? part :>

Any help is greatly appreciated.

Thx!

[Lee]

tg****@gmail.com said:

I need to replace a number in a string

str = "http://www.example.com?test=1&cat=0&ref=123213123213";

I want to replace the 0 after the cat= part with a new number. 0 could
be any number though so i need to use a reg exp to replace it.

str = str.replace(??????,newnumber);

I need help with the ?????? part :>

str = str.replace(/cat=\d+/,"cat="+newnumber);